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3 years ago

Help!!

Physics

2 answers:

scZoUnD [109]3 years ago

7 0

If Fg=mg=ma and, Fg(planetX)=1/5Fg(earth)

then the time would be 5x of the time as gravity is acceleration. So 3.9s*5=19.5s

As the force of gravity is less, then the acceleration of masses is also less, therefore it will take more time for the object to fall by the factor of the force of gravity difference

Neko [114]3 years ago

4 0

D= 1/2 g T^2

T = √(2D/g)

If g changes to g/5, then T increases by the factor √5 .

If it was originally 3.9 sec, then the new T is 8.72 sec.

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What an object is placed 8 mm from a concave spherical mirror a clear image can be projected on the screen 16 mm in front of me

alexgriva [62]

Concept: The magnification of spherical mirror can be defined by two ways.

(i) In terms of the height of the object and image.

The magnification of the spherical mirror is defined as the ratio of the height of the image' $h_{i}$ ' to the height of the object ' $h_{o}$ '. It is denoted by letter 'm'.

Mathematically, it can be written as

$m= \frac{h_{i}}{h_{o}} ------------(1)$

(ii) In terms of the object's and image's distances.

The magnification of the spherical mirror is defined as the negative ratio of the image distance' $d_{i}$ ' to the object distance ' $d_{o}$ '.

Mathematically, it can be written as

$m= - \frac{d_{i}}{d_{o}} ------------(2)$

Now, from equation (1) and (2) we have,

$m = \frac{h_{i}}{h_{o}} = - \frac{d_{i}}{d_{o}} -----------(3)$

Given: Spherical Concave Mirror,

We will consider positive sign for object's and image's distance because both are in front of the mirror.

Object distance $(d_{o}) = + 8 mm$ .

Image distance $(d_{i}) = + 16 mm$

Object's height $(h_{o}) = + 4 mm$

Image's height $(h_{i}) =?$

Now, apply equation (3)

$\frac{h_{i}}{h_{o}} = - \frac{d_{i}}{d_{o}}$

$Or, \frac{h_{i}}{4 mm} = - \frac{+16 mm}{+8 mm}$

Or, hi = - 8 mm

Here; negative sign means, the image will be inverted.

The image's height will be 8 mm.

4 0

3 years ago

An upright spring with a 96g mass on it is compressed 2 cm. When

Alexeev081 [22]

Answer:

I only know answer A and it's 2825.28 N/m, with rounding it's 2825.5

Explanation:

Use the m*g*h=1/2*k*x^2 equation

96*9.81*60=1/2*k*2^2

5650.56=2k

5650.56/2=2825.28N/m

8 0

3 years ago

A block of mass m1 = 3.5 kg moves with velocity v1 = 6.3 m/s on a frictionless surface. it collides with block of mass m2 = 1.7

maxonik [38]

First, let's find the speed $v_i$ of the two blocks m1 and m2 sticked together after the collision.
We can use the conservation of momentum to solve this part. Initially, block 2 is stationary, so only block 1 has momentum different from zero, and it is:
$p_i = m_1 v_1$
After the collision, the two blocks stick together and so now they have mass $m_1 +m_2$ and they are moving with speed $v_i$ :
$p_f = (m_1 + m_2)v_i$
For conservation of momentum
$p_i=p_f$
So we can write
$m_1 v_1 = (m_1 +m_2)v_i$
From which we find
$v_i = \frac{m_1 v_1}{m_1+m_2}= \frac{(3.5 kg)(6.3 m/s)}{3.5 kg+1.7 kg}=4.2 m/s$

The two blocks enter the rough path with this velocity, then they are decelerated because of the frictional force $\mu (m_1+m_2)g$ . The work done by the frictional force to stop the two blocks is
$\mu (m_1+m_2)g d$
where d is the distance covered by the two blocks before stopping.
The initial kinetic energy of the two blocks together, just before entering the rough path, is
$\frac{1}{2} (m_1+m_2)v_i^2$
When the two blocks stop, all this kinetic energy is lost, because their velocity becomes zero; for the work-energy theorem, the loss in kinetic energy must be equal to the work done by the frictional force:
$\frac{1}{2} (m_1+m_2)v_i^2 =\mu (m_1+m_2)g d$
From which we can find the value of the coefficient of kinetic friction:
$\mu = \frac{v_i^2}{2gd}= \frac{(4.2 m/s)^2}{2(9.81 m/s^2)(1.85 m)}=0.49$

3 0

3 years ago

que ventajas e inconvenientes tienen las energias renovables, el agua del mar, agua embalzada, el sol, el viento

ahrayia [7]

Answer:

Ventajas ambientales:

La principal ventaja es la prácticamente es nula la emisión de gases de efecto invernadero (GEI).

* Ayudan a disminuir enfermedades relacionadas con la contaminación.

* No necesitan grandes cantidades de agua para su funcionamiento.

* No crean problemas de basura difíciles de resolver, como la eliminación de residuos nucleares o escorias.

Ventajas económicas:

*Generación de empleos directos (trabajadores de la construcción, desarrolladores, fabricantes de equipo, diseñadores, instaladores, financieros).

* Competencia y reducción de precios de las generadoras tradicionales por tener un nuevo competidor, que asegure confiabilidad del servicio.

ENERGÍA SOLAR INCONVENIENTES:

La instalación de paneles solares en casas o industrias no es barato, además no todas las vivienda pueden instalarse este tipo de paneles. La legislación en cuanto al uso de los paneles solares no es la misma en todo el mundo.

ENERGÍA EÓLICA INCONVENIENTES:

La creación de parques eólicos es muy cara, además hay colectivos que se opinen a la instalación de parques eólicos en tierra porque opinan que afea el paisaje y es peligrosos para las aves que chocan al volar cerca de las hélices de los generadores eólicos.

ENERGÍA DE LAS MAREAS INCONVENIENTES:

El movimiento de las mareas mueve las turbinas. El movimiento de las mareas es capaz de mover turbinas, pero para ello hay que construir represas o aluviones.

Entre los inconvenientes está que la construcción de aluviones es muy cara. Hay oposición de grupos ecologistas que destacan que esta energía puede tener un impacto negativo sobre la fauna acuática. La energía de las mareas puede reducir el flujo de las mareas e impedir el flujo de aguas residuales al mar.

Explanation:

5 0

3 years ago

A thin double convex glass lens with an index of 1.56 while surrounded by air has a 10 cm focal length. If it is placed under wa

bearhunter [10]

Explanation:

Formula which holds true for a leans with radii $R_{1}$ and $R_{2}$ and index refraction n is given as follows.