In double displacement reactions, the metals in each compound are switching to form new compounds.

Chemistry

1 answer:

valentinak56 [21]3 years ago

8 0

Answer:

Yes it is because of the fact that they are leaving a negatively charged ion and that ion needs to bind with any free metal and note only a metal that is high than the other in the reactivity series can displace the other.

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A solution has a [OH−] of 1 x 10−12. What is the pOH of this solution?<br> 2<br> 7<br> 10<br> 12

strojnjashka [21]

-log (1×10^-12) is how you calculate the pOH which in this case is 12

7 0

3 years ago

Read 2 more answers

A certain substance X has a normal freezing point of -6.4 C and a molal freezing point depression constant Kf= 3.96 degrees C.kg

Brut [27]

Answer: $1.0\times 10^2g$

Explanation:

Depression in freezing point is given by:

$\Delta T_f=i\times K_f\times m$

$\Delta T_f=T_f^0-T_f=(-6.4-(13.6))^0C=7.2^0C$ = Depression in freezing point

i= vant hoff factor = 1 (for non electrolyte like urea)

$K_f$ = freezing point constant = $3.96^0C/m$

m= molality

$\Delta T_f=i\times K_f\times \frac{\text{mass of solute}}{\text{molar mass of solute}}\times \text{weight of solvent in kg}}$

Weight of solvent (X)= 950 g = 0.95 kg

Molar mass of non electrolyte (urea) = 60.06 g/mol

Mass of non electrolyte (urea) added = ?

$7.2=1\times 3.96\times \frac{xg}{60.06 g/mol\times 0.95kg}$

$x=1.0\times 10^2g$

Thus $1.0\times 10^2g$ urea was dissolved.

8 0

3 years ago

A solution of silver chlorate reacts with a solution of lithium iodide.

Anettt [7]

Answer: $Ag^+(aq)+I^-(aq)\rightarrow AgI(s)$

Explanation:

A double displacement reaction is one in which exchange of ions take place. The salts which are soluble in water are designated by symbol (aq) and those which are insoluble in water and remain in solid form are represented by (s) after their chemical formulas.

Spectator ions are defined as the ions which does not get involved in a chemical equation or they are ions which are found on both the sides of the chemical reaction present in ionic form.

The given chemical equation is:

$AgClO_3(aq)+LiI(aq)\rightarrow AgI(s)+LiClO_3(aq)$