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Murljashka [212]
3 years ago
7

Given the front and right views, create an AutoCAD isometric of the object. Save the drawing as lab5c.dwg. Grid size is 10mm. Yo

u may approximate the location of the hidden line as long as it is consistent with the other view.
Engineering
1 answer:
ki77a [65]3 years ago
4 0

Given the front and right views, create an AutoCAD isometric of the object. Save the drawing as lab5c.dwg. Grid size is 10mm. You may approximate the location of the hidden line as long as it is consistent with the other view is given below

Explanation:

1.Use CTRL-C to copy the lines to the Windows clipboard. Go to the 2D drawing and give the PASTESPEC (Paste Special) command. This will paste an image of the selected geometry into the other drawing. SInce it is an image and not AutoCAD entities the image quality will be limited.

2.Isometric drawing in AutoCAD 2014 and older versions:

At first, you need to change your snap settings to isometric. Type DS on the command line and press enter. Drafting settings window will pop up from this window select snap and grid tab and make sure Isometric snap radio button is checked.

3.To Display a Preset 3D View

Click View tab Views panel View Manager. Find. The View tab is not displayed by default, so an alternative method is to enter VIEW at the Command prompt. You can also employ the ViewCube in the top-right corner of the drawing area.

Select a preset view (Top, Bottom, Left, and so on).

4.If you aren't in model space, double-click inside the viewport to enter model space.

Go to Home tab > Modify panel (expanded)> Change Space to start the CHSPACE command.

At the prompt, select one or more objects to move.

Press Enter to end selection and the command. AutoCAD moves the selected objects to the other space.

5.

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What is the voltage output (in V) of a transformer used for rechargeable flashlight batteries, if its primary has 515 turns, its
kow [346]
<h2>Answer:</h2>

7532V

<h2>Explanation:</h2>

For a given transformer, the ratio of the number of turns in its primary coil (N_{p}) to the number of turns in its secondary coil (N_{s}) is equal to the ratio of the input voltage (V_{p}) to the output voltage (V_{s}) of the transformer. i.e

\frac{N_p}{N_s} = \frac{V_p}{V_s}            ----------------(i)

<em>From the question;</em>

N_{p} = number of turns in the primary coil = 8 turns

N_{s} = number of turns in the secondary coil = 515 turns

V_{p} = input voltage = 117V

<em>Substitute these values into equation (i) as follows;</em>

\frac{8}{515} = \frac{117}{V_s}

<em>Solve for </em>V_{s}<em>;</em>

V_{s} = 117 x 515 / 8

V_{s} = 7532V

Therefore, the output voltage (in V) of the transformer is 7532

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3 years ago
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Answer:

two

Explanation:

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B. When a trivalence impurity is added to semiconductor, instead of excess electron, there will be excess hole created by crystals. Reason for this attribute is the trivalence atom will replace some tetra valence semiconductor atom, when three valence electrons of the 3 valence electrons of the trivalent impurity atom make bond with three neighbouring semiconductor which gives rise to lack of electron in the bond of the fourth neighbouring semiconductor which contribute a whole to the crystalline since trivalent impurity contribute excess holes to the crystal of semi conductor, this holes can accept electrons.

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Explanation:

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