Dunno what to ask, okbye

Build a 3-input XOR gate using a 3x8 decoder and an Or gate.please Quickly i have final

lana [24]

Answer:

Take a 3 to 8 decoder with active low outputs

Assuming you are familiar with the functioning of decoders,

The three inputs of decoder of course are the first, second and the carry bit which you feed to the subtractor.

Next we examine the truth table of the full subtractor i formatted in the picture.

Then write the minterms for the difference output and borrow output from the given truth table picture I have mentioned before!!

Explanation:

hopi it to help you!!

7 0

2 years ago

I don’t get this it’s hella hard

qwelly [4]

Answer:

V₂ = 20 V

Vt = 20 V

V₁ = 20 V

V₃ = 20 V

I₁ = 10 mA

I₃ = 3.33 mA

It = 18.33 mA

Rt = 1090.91 Ω

Pt = 0.367 W

P₁ = 0.2 W

P₂ = 0.1 W

P₃ = 0.067 W

Explanation:

Part of the picture is cut off. I assume there is a voltage source Vt there?

First, use Ohm's law to find V₂.

V = IR

V₂ = (0.005 A) (4000 Ω)

V₂ = 20 V

R₁ and R₃ are in parallel with R₂ and the voltage source Vt. That means V₁ = V₂ = V₃ = Vt.

V₁ = 20 V

V₃ = 20 V

Vt = 20 V

Now we can use Ohm's law again to find I₁ and I₃.

V = IR

I = V/R

I₁ = (20 V) / (2000 Ω)

I₁ = 0.01 A = 10 mA

I₃ = (20 V) / (6000 Ω)

I₃ = 0.00333 A = 3.33 mA

The current It passing through Vt is the sum of the currents in each branch.

It = I₁ + I₂ + I₃

It = 10 mA + 5 mA + 3.33 mA

It = 18.33 mA

The total resistance is the resistance of the parallel resistors:

1/Rt = 1/R₁ + 1/R₂ + 1/R₃

1/Rt = 1/2000 + 1/4000 + 1/6000

Rt = 1090.91 Ω

Finally, the power is simply each voltage times the corresponding current.

P = IV

Pt = (0.01833 A) (20 V)

Pt = 0.367 W

P₁ = (0.010 A) (20 V)

P₁ = 0.2 W

P₂ = (0.005 A) (20 V)

P₂ = 0.1 W

P₃ = (0.00333 A) (20 V)

P₃ = 0.067 W

7 0

3 years ago

A tubular reactor has been sized to obtain 98% conversion and to process 0.03 m^3/s. The reaction is a first-order irreversible

Zolol [24]

Answer:

The conversion in the real reactor is = 88%

Explanation:

conversion = 98% = 0.98

process rate = 0.03 m^3/s

length of reactor = 3 m

cross sectional area of reactor = 25 dm^2

pulse tracer test results on the reactor :

mean residence time ( tm) = 10 s and variance (∝2) = 65 s^2

note: space time (t) =

t = $\frac{A*L}{Vo}$ Vo = flow metric flow rate , L = length of reactor , A = cross sectional area of the reactor

therefore (t) = $\frac{25*3*10^{-2} }{0.03}$ = 25 s

since the reaction is in first order

X = 1 - $e^{-kt}$

$e^{-kt}$ = 1 - X

kt = In $\frac{1}{1-X}$

k = In $\frac{1}{1-X}$ / t

X = 98% = 0.98 (conversion in PFR ) insert the value into the above equation then

K = 0.156 $s^{-1}$

Calculating Da for a closed vessel

; Da = tk

= 25 * 0.156 = 3.9

calculate Peclet number Per using this equation

0.65 = $\frac{2}{Per} - \frac{2}{Per^2} ( 1 - e^{-per})$

therefore

$\frac{2}{Per} - \frac{2}{Per^2} (1 - e^{-per}) - 0.65 = 0$

solving the Non-linear equation above( Per = 1.5 )

Attached is the Remaining part of the solution

3 0

3 years ago

You plan to install an active, liquid-based solar heating system for hot water. There are four candidate collector systems. Your

olchik [2.2K]

Solution:

The given formula,

$x=F_{R} U_{L} \times \frac{P l}{F R_{1}} \times\left(T_{r e f}-\bar{T}_{a}\right) \Delta t \times \frac{A_{c}}{L}$

$y=F_{R}(\tau \alpha)_{n} x \frac{F_{R}^{\prime}}{F_{R}} \times \frac{(\bar{\tau} d)}{(T d)_{n}} \times \bar{H}_{T} N \times \frac{A C}{L}$

$\frac{x}{y}=\frac{ u_{L} \times\left(T_{x t}-\bar{T}_{a}\right) \times \Delta t}{\left(\tau_{x}\right)_{h} \times\left(\frac{\bar{\tau}_{d}}{\left.| \tau_{d}\right)_{n}}\right) \times \bar{H}+N}$

From the table,

$1) $\quad x=2 \cdot 87, \quad y=0.96$\\$\frac{x}{y}=\frac{2187}{0.96}$22895\\\\2) $x=3 \cdot 466 \cdot y=6 \cdot 998$\\$\frac{x}{y}=\frac{3 \cdot 466}{0.898}$$=3 \cdot 4729$$

$3$x=3 \cdot 229, y=1 \cdot 08$\\$\frac{x}{x}=\frac{3 \cdot 229}{1 \cdot 08}$\\=2.9898\)\\\\4) $x=6.525, y=1.094$\\$\frac{x}{y}=\frac{5.625}{1.094}$\\=5.0502$

8 0

3 years ago

While out on the International Space Station, an engineer was able to gather a sample of a new type of unidentified rock. What k

kvasek [131]

Answer:

geology and engineering

Explanation:

In this specific scenario, the engineer would use all of his geology and engineering knowledge in order to discover some of the potential uses. This is because the field of geology focuses on understanding rocks and all the minerals that make up that specific rock. While engineers focus on finding new ways to get certain tasks done through new technology and resources. By putting his/her knowledge of both of these tasks, the engineer can quickly determine the potential that the newly discovered rock has and the value that it can bring.

3 0

3 years ago

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