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2 years ago

Draw a surface development of a truncated cone

Engineering

1 answer:

Vanyuwa [196]2 years ago

6 0

The image of the drawing of a surface development of a truncated cone is given in the image attached.

<h3>What is truncated cone?</h3>

The term truncated cone is defined as any section of a cone or a pyramid that is said to not have a tip and it is one that ends in a plane that is often parallel to the base.

So therefore, The image of the drawing of a surface development of a truncated cone is given in the image attached.

Learn more about truncated cone from

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53.67

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2 years ago

For a fluid with a Prandtl Number of 1000.0, the hydrodynamic layer is thinner than the thermal boundary layers. a) True b) Fals

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Answer:

(b)False

Explanation:

Given:

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Prandtl number(Pr) can also be defined as

$Pr=\left (\dfrac{\delta }{\delta _t}\right )^3$

Where $\delta$ is the hydrodynamic boundary layer thickness and $\delta_t$ is the thermal boundary layer thickness.

So if Pr>1 then hydrodynamic boundary layer thickness will be greater than thermal boundary layer thickness.

In given question Pr>1 so hydrodynamic boundary layer thickness will be greater than thermal boundary layer thickness.

So hydrodynamic layer will be thicker than the thermal boundary layer.

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3 years ago

All of these are uses of microwaves except...

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2 years ago

A particular motor rotates at 3000 revolutions per minute. What is its speed in rad/sec, and how many seconds does it takes to m

Leno4ka [110]

Answer:

ω=314.15 rad/s.

0.02 s.

Explanation:

Given that

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$\omega=\dfrac{2\pi N}{60}\ rad/s$

Now by putting the values in the above equation

$\omega=\dfrac{2\pi \times 3000}{60}\ rad/s$

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Therefore the speed in rad/s will be 314.15 rad/s.

The speed in rev/sec given as

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That is why to cover 1 revolution it take

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2 years ago

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Answer:

B. The thickness of the heated region near the plate is increasing.

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3 years ago