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labwork [276]
3 years ago
14

A custom t shirt company charges a $200 set up fee and $5 per t shirt. Approximately how may t shirts must be produced so that t

he total cost per t shirt is $5.33?
a.1,000 tshirts
b.200 tshirts
c.600 tshirts
d.1,266
Mathematics
1 answer:
dolphi86 [110]3 years ago
6 0
To find the number of t-shirts, we must add the individual cost of producing 1 shirt and equate it to 5.33. Since 200 is the cost of the set-up fee, we divide this by an unknown x, for the individual cost. We add 5, which is the cost to produce a shirt. We now have 200/x + 5 = 5.33. Find the value of x, which is 606, nearest to 600. Therefore approximately 600 t-shirts must be produced.
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antiseptic1488 [7]
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3 years ago
Evaluate the expression if a=2,b=-3,C=-1, and D=4<br><br><br> -2(b^2-5c)
Alenkasestr [34]

\qquad \qquad  \bf \huge\star \:  \:  \large{  \underline{Answer} }  \huge \:  \: \star

  • Equivalent value = -28

\textsf{  \underline{\underline{Steps to solve the problem} }:}

\qquad❖ \:  \sf \: - 2( {b}^{2}  - 5c)

( put the values )

\qquad❖ \:  \sf \: - 2 \{( - 3) {}^{2}  - 5( - 1) \}

\qquad❖ \:  \sf \: - 2(9 -  (- 5))

\qquad❖ \:  \sf \: - 2(9 + 5)

\qquad❖ \:  \sf \: - 2 \times 14

\qquad❖ \:  \sf \: - 28

\qquad \large \sf {Conclusion}  :

  • -2(b² - 5c) = -28

7 0
1 year ago
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vfiekz [6]

Answer:

17.1

Step-by-step explanation:

If you have 15.50 and you divide 0.75 you get 20.6 and if you subtract 3.50 you get 17.1 which is your answer. Boom

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amid [387]

Answer:

---> --->  

WS  DS

Step-by-step explanation:

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A farmer wants to fence a rectangular habitat for goats. The length (y) of the habitat has to be at least 80 feet. The farmer cu
Leni [432]

Answer:

  d. The farmer can make a habitat that is 40 feet wide and 100 feet long.

Step-by-step explanation:

The attached graph shows the inequalities and the various answer choices. The existence of the doubly-shaded area shows that answer choice C is false.

The appropriate choice is ...

  d. The farmer can make a habitat that is 40 feet wide and 100 feet long.

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