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valentina_108 [34]
3 years ago
5

The picture shows two liquid samples are poured into a beaker. As shown, the liquids don’t mix with each other. Which statement

is true?
A) Sample A has greater density.
B) Sample B has greater density.
C) The densities are the same because the volumes are the same.
D)The densities are different because the volumes are different.

Chemistry
1 answer:
Nesterboy [21]3 years ago
7 0

The answer is A. The volume lines on the bottom are just showing the volume of the beaker. The more dense liquid will sink to the bottom
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26Fe59 ----> -1e0 + 27Co59
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2 years ago
You and your lab partner are asked to determine the density of an aluminum bar. The mass is known accurately to 4 significant fi
zmey [24]

Answer:

Average density for method A = 2.4 g/cm³

Average density for method B = 2.605 g/cm³

Explanation:

In order to calculate the average density for each method, we need to add the data for each method, and then divide the result by the number of measurements (in this case is 4 for both methods):

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3 years ago
Aluminum chloride is added to cesium does a single replacement reaction occur, and if so what is the correct chemical equation f
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5 0
2 years ago
Read 2 more answers
What is the pH of a mixture of 0.042 M NaH2PO4 and 0.058 M Na2HPO4? Hint: The pKa of phosphate is 6.86.
AlekseyPX

Answer:

The pH value of the mixture will be 7.00

Explanation:

Mono and disodium hydrogen phosphate mixture act as a buffer to maintain pH value around 7. Henderson–Hasselbalch equation is used to determine the pH value of a buffer mixture, which is mathematically expressed as,

pH=pK_{a} + log(\frac{[Base]}{[Acid]})

According to the given conditions, the equation will become as follow

pH=pK_{a} + log(\frac{[Na_{2}HPO_{4} ]}{[NaH_{2}PO_{4}]})

The base and acid are assigned by observing the pKa values of both the compounds; smaller value means more acidic. NaH₂PO₄ has a pKa value of 6.86, while Na₂HPO₄ has a pKa value of 12.32 (not given, but it's a constant). Another more easy way is to the count the acidic hydrogen in the molecular formula; the compound with more acidic hydrogens will be assigned acidic and vice versa.

Placing all the given data we obtain,

pH=6.86 + log(\frac{0.058}{0.042})

pH=7.00

5 0
3 years ago
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