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joja [24]
3 years ago
6

3. The soccer kicker kicks a 2 kg football with a force of 68 N. How fast will the ball accelerate down the field?

Physics
1 answer:
Katen [24]3 years ago
6 0

Answer:

\boxed {\boxed {\sf m= 2 \ kg , \\a= 34 \ m/s^2,  \\\F= 68 \ N}}

Explanation:

The formula for force is:

F=m*a

If we rearrange the formula to solve for a (acceleration), the formula becomes

\frac{F}{m} =a

The force is 68 Newtons. Let's convert the units to make the problem easier later on. 1 N is equal to 1 kg*m/s², so the force of 68 N is equal to 68 kg*m/s².

The mass is 2 kilograms.

F=68 \ kg*m/s^2 \\m= 2\ kg

Substitute the values into the formula.

\frac{68 \ kg*m/s^2}{2 \ kg} =a

Divide. Note that the kilograms will cancel each other out (hence why we changed the units).

\frac{68 \ m/s^2}{2}=a

34 \ m/s^2=a

The acceleration is<u> </u><u>34 meters per second squared.</u>

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1)The position change of almost any manually operated room light switch.

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4 0
3 years ago
What will happen if a car experiences a 300 N force to the right from the engine and a separate 150 N force due to friction and
gayaneshka [121]

Force applied on the car due to engine is given as

F_1 = 300 N towards right

Also there is a force on the car towards left due to air drag

F_2 = 150 N towards left

now the net force on the car will be given as

\vec F_{net} = \vec F_1 + \vec F_2

now we can say that since the two forces are here opposite in direction so here the vector sum of two forces will be the algebraic difference of the two forces.

So we can say

F_{net} = F_1 - F_2

F_{net} = 300 - 150

F_[net} = 150 N

So here net force on the car will be 150 N towards right and hence it will accelerate due to same force.

5 0
3 years ago
Any help would be great! Thank you x<br><br><br> Giving brainliest answer xoxo
garri49 [273]

Answer:

A vacuum would have been created. I hope this helps have a great day

3 0
3 years ago
1. In Newton’s ring experiment, the diameter of the 5th ring is 0.30 cm and diameter of 15th the ring is 0.62 cm. Find the diame
IgorC [24]

Answer:

Diameter of Newton’s 5th ring = 0.30 cm

Diameter of Newton’s 15th ring = 0.62 cm

Diameter of Newton’s 25th ring = ?

From Newton’s rings experiment we infer that

D2n+m − D2n = 4λmR

For the 5th and 15th rings we have

D215 − D25 = 4λ * 10 * R _______ (1) (m = 10)

For 15th and 25th rings

D225 − D215 = 4λ * 10 * R _______ (2) (m = 10)

We equate the two derivatives

Equation (2) = Equation (1)

D225 − D215 = D215 − D25

D225 = 2D215 – D25

Substituting the values into the equation

D225 = 2 * 0.62 * 0.62 – 0.3 * 0.3 =0.6788 cm2

D25 = 0.8239 cm

4 0
3 years ago
Need amswer fast plz
FrozenT [24]

Answer:

I need this for may schooling

6 0
2 years ago
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