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3 years ago

3. The soccer kicker kicks a 2 kg football with a force of 68 N. How fast will the ball accelerate down the field?

Physics

1 answer:

Katen [24]3 years ago

6 0

Answer:

$\boxed {\boxed {\sf m= 2 \ kg , \\a= 34 \ m/s^2, \\\F= 68 \ N}}$

Explanation:

The formula for force is:

$F=m*a$

If we rearrange the formula to solve for a (acceleration), the formula becomes

$\frac{F}{m} =a$

The force is 68 Newtons. Let's convert the units to make the problem easier later on. 1 N is equal to 1 kg*m/s², so the force of 68 N is equal to 68 kg*m/s².

The mass is 2 kilograms.

$F=68 \ kg*m/s^2 \\m= 2\ kg$

Substitute the values into the formula.

$\frac{68 \ kg*m/s^2}{2 \ kg} =a$

Divide. Note that the kilograms will cancel each other out (hence why we changed the units).

$\frac{68 \ m/s^2}{2}=a$

$34 \ m/s^2=a$

The acceleration is<u> </u><u>34 meters per second squared.</u>

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A cube of wood having an edge dimension of 20.0cm and a density of 650 kg /m³ floats on water. (b) What mass of lead should be p

schepotkina [342]

The mass added is "m" so the complete cube is submerged in the water is 2.8 kg.

<h3>What mass of lead should be placed on the cube?</h3>

Given: Side of the cube (a) = 20cm

The density of the cube (ρc) = $$$650 kg/m^3$

a) Applying the force balance, the buoyant force must be equal to the weight of the cube

ρcgV = ρg × (Ax)

Substituting the values in the above equation, we get

$(650*(0.2 m)^3)=1000*(0.2 m)^2*x$

x = 0.13

where x is the height of the cube in the water

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ρ is the density of the water

V is the volume of the cube

Now, the height above the surface of the water would be

h = a − x

Substituting the values, then we get

h = 0.2 − 0.13

h = 0.07 m

b) The mass added is "m" so the complete cube is submerged in the water, therefore

ρcgV + mg = ρg × (V)

$$(650*(0.2 m)^3)+m=1000*(0.2 m)^3$

m = 2.8 kg

The mass added is "m" so the complete cube is submerged in the water is 2.8 kg.

To learn more about buoyant force refer to:

brainly.com/question/11884584

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1 year ago

A disk of mass m and moment of inertia of I is spinning freely at 6.00 rad/s when a second identical disk, initially not spinnin

Nadusha1986 [10]

Answer:

The angular speed of the new system is $3\,\frac{rad}{s}$ .

Explanation:

Due to the absence of external forces between both disks, the Principle of Angular Momentum Conservation is observed. Since axes of rotation of each disk coincide with each other, the principle can be simplified into its scalar form. The magnitude of the Angular Momentum is equal to the product of the moment of inertial and angular speed. When both disks begin to rotate, moment of inertia is doubled and angular speed halved. That is:

$I\cdot \omega_{o} = 2\cdot I \cdot \omega_{f}$

Where:

$I$ - Moment of inertia of a disk, measured in kilogram-square meter.

$\omega_{o}$ - Initial angular speed, measured in radians per second.

$\omega_{f}$ - Final angular speed, measured in radians per second.

This relationship is simplified and final angular speed can be determined in terms of initial angular speed:

$\omega_{f} = \frac{1}{2}\cdot \omega_{o}$

Given that $\omega_{o} = 6\,\frac{rad}{s}$ , the angular speed of the new system is:

$\omega_{f} = \frac{1}{2}\cdot \left(6\,\frac{rad}{s} \right)$

$\omega_{f} = 3\,\frac{rad}{s}$

The angular speed of the new system is $3\,\frac{rad}{s}$ .

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A box-shaped metal can has dimensions 5 in. by 19 in. by 4 in. high. All of the air inside the can is removed with a vacuum pump

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Answer:

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Explanation:

From the question we are told that

The length of the box is $l = 19 \ in$

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$p = \frac{F}{A}$

Where A is the area of the box which is mathematically evaluated as

$A = l * w$

substituting values

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$A = 95 \ in^2$

This pressure is equivalent to the atmospheric pressure which has a constant value of $p = 14.7 pi$

This implies that

$14.7 = \frac{F}{95}$

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3 years ago

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Answer:

When you blow into a tuba the air vibrates very slowly.

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