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Tema [17]
3 years ago
11

Studying climate on other planets is important to understanding climate on earth because

Physics
1 answer:
zhenek [66]3 years ago
6 0

Answer:

yes it is important.

Explanation:

It is important to study the climate of other planet to understand the climate of the earth because it is useful to know which things are harmful for our earth and which are important for our earth climate comparing with the other planets.

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PLEASE HELP ME!<br><br> How do you think the swarms affect local populations of humans?
Volgvan

Answer:

by temperature

Explanation:

cuz

5 0
3 years ago
when a constant force acts upon an object the acceleration of the object varies inversely with its mass. when a certain constant
solong [7]

Explanation:

When a constant force acts upon an object the acceleration of the object varies inversely with its mass.

a\propto \dfrac{1}{m}

or

\dfrac{a_1}{a_2}=\dfrac{m_2}{m_1}

If m₁ = 21 kg, a₁ = 3 m/s², m₂ = 9 kg

We need to find a₂

So,

a_2=\dfrac{m_1a_1}{m_2}\\\\a_2=\dfrac{21\times 3}{9}\\\\a_2=7\ m/s^2

So, if mass is 9 kg, its acceleration is 7 m/s².

8 0
3 years ago
How does the heat enhance <br>the rate of chemical reaction ? Explain in short.​
densk [106]
When the reactants are heated, the average kinetic energy of the molecules increases. This means that more molecules are moving faster and hitting each other with more energy. If more molecules hit each other with enough energy to react, then the rate of the reaction increases.
3 0
3 years ago
Two carts, one of mass 2m and one of mass m, approach each other with the same speed, v. When the carts collide, they hook toget
Nikitich [7]

Answer:

<em>Second option</em>

Explanation:

<u>Linear Momentum</u>

The linear momentum of an object of mass m and speed v is

P=mv

If two or more objects are interacting in the same axis, the total momentum is

P_t=m_1v_1+m_2v_2+...

Where the speeds must be signed according to a fixed reference

The images show a cart of mass 2m moves to the left with speed v since our reference is positive to the right

P_1=-2mv

The second cart of mass m goes to the right at a speed v

P_2=mv

The total momentum before the impact is

P_t=-2mv+mv=-mv

The total momentum after the collision is negative, both carts will join and go to the left side

The first option shows both carts with the same momentum before the collision and therefore, zero momentum after. It's not correct as we have already proven

The third option shows the 2m cart has a positive greater momentum than the other one. We have proven the 2m car has negative momentum. This option is not correct either

The fourth option shows the two carts keep separated after the collision, which contradicts the condition of the question regarding "they hook together".

The second option is the correct one because the mass m_2 has a negative momentum and then the sum of both masses keeps being negative

3 0
3 years ago
Read 2 more answers
You are observing a spacecraft moving in a circular orbit of radius 100,000 km around a distant planet. You happen to be located
Natalija [7]

To solve this problem we will apply the concepts related to centripetal acceleration, which will be the same - by balance - to the force of gravity on the body. To find this acceleration we must first find the orbital velocity through the Doppler formulas for the given periodic signals. In this way:

v_{o} = c (\frac{\lambda_{max}-\bar{\lambda}}{\bar{\lambda}}})

Here,

v_{o} =  Orbital Velocity

\lambda_{max} = Maximal Wavelength

\bar{\lambda}} = Average Wavelength

c = Speed of light

Replacing with our values we have that,

v_{o} = (3*10^5) (\frac{3.00036-3}{3})

<em>Note that the average signal is 3.000000m</em>

v_o = 36 km/s

Now using the definition about centripetal acceleration we have,

a_c = \frac{v^2}{r}

Here,

v = Orbit Velocity

r = Radius of Orbit

Replacing with our values,

a = \frac{(36km/s)^2}{100000km}

a= 0.01296km/s^2

a = 12.96m/s^2

Applying Newton's equation for acceleration due to gravity,

a =\frac{GM}{r^2}

Here,

G = Universal gravitational constant

M = Mass of the planet

r = Orbit

The acceleration due to gravity is the same as the previous centripetal acceleration by equilibrium, then rearranging to find the mass we have,

M = \frac{ar^2}{G}

M = \frac{(12.96)(100000000)^2}{ 6.67*10^{-11}}

M = 1.943028*10^{27}kg

Therefore the mass of the planet is 1.943028*10^{27}kg

7 0
3 years ago
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