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In a manufacturing process, a large, cylindrical roller is used to flatten material fed beneath it. The diameter of the roller i

kotykmax [81]

The maximum angular speed of the roller is 3.47rad/a,

the maximum tangential speed of the point an the rim of the roller is 1.47m/s,

the time t should the driven force be removed from the roller so that the roller does not reverse its direction of rotation is t = 2.78s,

5.4 rotation has the roller turned between t=0 and the time found in part c

<h3>What does tangential speed refer to?</h3>

Any item moving along a circular path has a linear component to its speed called tangential velocity. An object's velocity is always pointed tangentially when it travels in a circle at a distance r from the center. The word for this is tangential velocity.

To calculate the tangential speed, divide the circumference by the time required to complete one spin. For instance, if it takes 12 seconds to complete one rotation, divide 18.84 by 12 to get 1.57 feet per second as the tangential velocity.

(a) angular speed w = dθ/dt = 5t - 1.8t^2

dw/dt = 5 - 3.6t = 0 for max w

so max w occurs at t = 5/3.6 s = 1.39s

so w max = 5*1.39 - 1.8*(1.39)^2 = 3.47 rad/s

(b) tangential speed v = r*w

r = D/2 = 0.5m

so v = 0.5*w = 1.74 m/s

(c) w is positive until 5t = 1.8t^2

so t = 5/1.8s = 2.78s (or t = 0 invalid)

After t = 2.87s, w is negative (starts reversing direction of rotation)

Driving force would actually have to be removed some time before t=2.78s because the roller can't stop instantaneously, but insufficient info to calculate this.

(d) Up to t = 2.78s, θ = 2.5*(2.78)^2 - 0.6*(2.78)^3 rad = 33.95 rad = 5.40 rotations

Therefore,

A) 3.47rad/a

B) 1.47m/s

C) t = 2.78s

D) 5.4 rotation

To learn more about tangential speed, refer to:

brainly.com/question/19660334

#SPJ4

4 0

2 years ago

Two parallel, circular conducting plates 32 cm in diameter are separated by 0.5 cm and have charges of +24 nC and -24 nC, respec

inysia [295]

Answer: E = 33762.39 N/c

Explanation: we calculate the capacitance of the two conducting plates ( this is because, 2 circular disc carrying opposite charges and the same dimension form a capacitor).

C = A/4πkd

Where C = capacitance of capacitor

A = Area of plates = πr² ( where r is radius which is half of the diameter)

K = electric constant = 9×10^9

d = distance between plates = 0.5cm = 0.005 m

Let us get the area, A = πr², where r = D/2 where D = diameter

r = 32/2 = 16cm = 0.16m

A = 22/7 × (0.16)² = 0.0804 m²

By substituting this into the capacitance formula, we have that

C = 0.0804/4×3.142*9×10^9 × 0.005

C = 0.0804/565486677.646

C = 142.17*10^(-12) F.

But C =Q/V where V = Ed

Hence we have that

C = Q/Ed

Where C = capacitance of capacitor = 142.17*10^(-12)F

Q = magnitude of charge on the capacitor = 24×10^-9c

E = strength of electric field =?

d = distance between plates = 0.005m

142.17*10^(-12) = 24 ×10^-9 / E × 0.005

By cross multiplying

142.17*10^(-12) × E × 0.005 = 24 ×10^-9

E = 24 ×10^-9 / 142.17*10^(-12) × 0.005

E = 33762.39 N/c

8 0

3 years ago

Light with a wavelength range of 141–295 nm shines on a silicon surface in a photoelectric effect apparatus, and a reversing pot

Ksju [112]

Answer:

a) the longest wavelength of the light that will eject electrons from the silicon surface is 258.7891 nm

b) maximum kinetic energy will electrons reach the anode is 0.5098 eV

Explanation:

Given:

Wavelength range = 141-295 nm

Potential of 3.5 V

For the silicon, the work function is Φ = 4.8 eV = 7.68x10⁻¹⁹J

Questions:

a) What is the longest wavelength of the light that will eject electrons from the silicon surface, λ = ?

b) With what maximum kinetic energy will electrons reach the anode,

a) The longest wavelength that will eject electrons:

$\lambda =\frac{hc}{\phi }$

Here

h = Planck's constant = 6.625x10⁻³⁴J s

c = speed of light = 3x10⁸m/s

Substituting values:

$\lambda =\frac{6.625x10^{-34}*3x10^{8} }{7.68x10^{-19} } =2.588x10^{-7} m=258.7891nm$

b) The maximum kinetic energy (one electron):

$K=\frac{hc}{\lambda } -\phi =\frac{6.625x10^{-34}*3x10^{8} }{141x10^{-9} } -7.68x10^{-19} =6.416x10^{-19} J=4.0098eV$

Now, you need to calculate the potential difference:

$K'=eV$

Here

e = charge of electron = 1.6x10⁻¹⁹C

Substituting:

$K'=1.6x10^{-19} *3.5=5.6x10^{-19} J=3.5eV$

Now, the maximum kinetic energy of the electrons:

Kmax = 4.0098 - 3.5 = 0.5098 eV

6 0

4 years ago

Match each word to its definition. current voltage resistance flow of electric charges arrowRight opposition to the flow of elec

lana66690 [7]

current . . . flow of electric charges

voltage . . . stored potential energy at the source of a circuit

resistance . . . opposition to the flow of electric current

arrowRight . . . a button on the computer keyboard that causes the cursor to move to the right on the screen when pushed

7 0

3 years ago

Read 2 more answers

Nuclear power plants produce useful energy by controlling the process of?

Mandarinka [93]

Nuclear fusion is thed answer

5 0

3 years ago

Read 2 more answers

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