Answer:
The volume of sodium hydroxide at the equivalence point is:
- <u>14.9 mL of sodium hydroxide</u>.
Explanation:
<u>The equivalence point occurs when, in this case, the HCl is completely neutralized with the solution of NaOH, how you can see this doesn't occur in the last point but occurs in the nineteenth point, where the pH is no more acid (below to 7) but is 11 approximately</u>, then you must see in the X-axis from this point and you can see the volume is almost 15, by this reason I calculate the valor of 14.9 milliliters.
Answer:
See explaination
Explanation:
1)
we know that
half cell with higher reduction potential is cathode
so
cathode :
N20 + 2H+ + 2e- ---> N2 + H20
anode :
Cr(s) ---> Cr+3 + 3e-
so
overall reaction is
3 N20 + 6H+ + 2 Cr ---> 3N2 + 3H20 + 2Cr+3
now
Eo cell = Eo cathode - Eo anode
so
EO cell = 1.77 + 0.74
Eo cell = 2.51 V
now
in this case
oxidizing agents are N20 and Cr+3
reducing agents are Cr and N2
higher the reduction potential , stronger the oxidizing agent
lower the reduction potential , stronger the reducing agent
so
oxidzing agents
N20 > Cr+3
reducing agents
Cr > N2
2)
cathode :
Au+ + e- --> Au
anode :
Cr ---> Cr+3 + 3e-
overall reaction
3Au+ + Cr ---> 3Au + Cr+3
Eo cell = 1.69 + 0.74
Eo cell = 2.43
now
oxidizing agents :
Au+ > Cr+3
reducing agents :
Cr > Au
3)
cathode :
N20 + 2H+ + 2e- ---> N2 + H20
andoe :
Au ---> Au+ + e-
overall
2 Au + N20 + 2H+ --> 2 Au+ + N2 + H20
Eo cell = 1.77 - 1.69
Eo cell = 0.08
oxidizing agents
N20 > Au+
reducing agents
Au > N2
Answer: Fluorine contains seven valence electrons. It needs one more electron to complete its octet. The oxidation number is 1- and indicates fluorine will gain or share one electron when it combines with another atom to become a more stable compound.
Explanation: Fluorine contains seven valence electrons. It needs one more electron to complete its octet. The oxidation number is 1- and indicates fluorine will gain or share one electron when it combines with another atom to become a more stable compound.
Temperature of gas at volume of 950 cm³ is 368.14K or 94.99⁰c.
- Volume is the amount of space a three-dimensional object takes up, expressed in cubic units.
- units of volume are mL, liter, cm³ or m³.
Given,
in this question, volume occupied by gas at 10.9⁰c is 733cm³.
we have to find out temperature at which gas occupies volume of 950 cm³.
First, convert temperature from celcius to Kelvin
10.9⁰c = 10.9 + 273.15 = 284.05 K
By equation or Boyle's Law
P1 x V1 / T1 = P2 x V2 / T2
Pressure is constant here
therefore, V1 / T1 = V2 / T2
here, V1 = 733 cm³
T1 = 284.05 K
V2 = 950 cm³
we have to find out T2
So, 733 / 284.05 = 950 / T2
T2 = 284.05 × 950 / 733 = 368.14 K
= 94. 99⁰c
Therefore the temperature of gas at volume of 950 cm³ is 368.14K or 94.99⁰c.
Learn more about Boyle's Law here:
https://brainly.in/question/2900894
#SPJ9
Solid liquid gas or plasma. Solid would be ice cubes (frozen state), liquid would be the water inside of the glass, the gas would be when you take that same water and place it on a stovetop to bring to a boiling point. (Gas state) and finally the plasma state is when you your gas particles (from the gas state) if you heat the gas particles, they will turn to plasma.