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navik [9.2K]
3 years ago
12

Plz help me.

Physics
2 answers:
Molodets [167]3 years ago
8 0

Answer:

52 meters

Explanation:

The man runs a distance D meters at 4 m/s.  The bear runs a distance D+26 meters at 6 m/s.

The time it takes the man to reach the vehicle is:

t = D / 4

The time it takes the bear to reach the vehicle is:

t = (D + 26) / 6

If they reach the vehicle at the same time:

D / 4 = (D + 26) / 6

6D = 4(D + 26)

6D = 4D + 104

2D = 104

D = 52

The man can return safely to his vehicle if D is less than 52 meters.

balandron [24]3 years ago
8 0

Answer:

52 meters

Explanation:

A man who gets off his vehicle keeps walking towards a forest on a straight path. He then observes a bear 26m ahead of him and turns back to run with a velocity of 4ms^-1 towards his vehicle which is located within a distance of 'D'.  If the bear chases the man with a velocity of 6ms^-1, the value of D for the man to safely return to his vehicle is 52 meters.

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A bicyclist starts at point P and travels around a triangular path that takes her through points Q and R before returning to the
REY [17]

Answer:

Displacement by cyclist is zero.

Explanation:

In the given question bicyclist is travelling in a rectangular track having P , Q and R edges.

The bicyclist starts from P and travel through Q and R and returned to P again.

We need to find its displacement.

We know displacement  of a body is its difference between its initial position to final position.

Here in the given question the bicyclist returns to P again.

Therefore, total displacement by bicyclist is zero.

Hence, this is the required solution.

4 0
4 years ago
Suppose it takes a constant force a time of 6.0 seconds to slow a 2500 kg truck
erastovalidia [21]

Answer:

3.3\cdot 10^3\:\mathrm{N}

Explanation:

Impulse on an object is given by \mathrm{[impulse]}=F\Delta t.

However, it's also given as change in momentum (impulse-momentum theorem).

Therefore, we can set the change in momentum equal to the former formula for impulse:

\Delta p=F\Delta t.

Momentum is given by p=mv. Because the truck's mass is maintained, only it's velocity is changing. Since the truck is being slowed from 26.0 m/s to 18.0 m/s, it's change in velocity is 8.0 m/s. Therefore, it's change in momentum is:

p=2500\cdot 8.0=20,000\:\mathrm{kg\cdot m/s}.

Now we plug in our values and solve:

\Delta p=F\Delta t,\\F=\frac{\Delta p}{\Delta t},\\F=\frac{20,000}{6}=\fbox{$3.3\cdot 10^3\:\mathrm{N}$}(two significant figures).

6 0
3 years ago
Finding the spring constant as shown, spring 3, which has an unknown spring constant k3, replaces spring 2. the mass of the weig
nevsk [136]
Replaces spring 2. the mass of the weight and pulley are unchanged: m=5.8 kg and mp=1.7 kg
6 0
4 years ago
A 500-g lump of clay is dropped onto a 1-kg cart moving at 60 cm/s. The clay is moving downward at 30 cm/s just before l dith t
viktelen [127]

Answer:

The speed of the cart and clay after the collision is 50 cm/s .

Explanation:

Given :

Mass of lump , m = 500 g = 0.5 kg .

Velocity of lump , v = 30 cm/s .

Mass of cart , M = 1 kg .

Velocity of cart , V = 60 cm/s .

We know by conservation of momentum :

mv+MV=(m+M)v'

Here , v' is the speed of the cart and clay after the collision .

Putting all value in above equation .

We get :

0.5\times 30+1\times 60=(0.5+1)\times v'\\\\v'=\dfrac{15+60}{1.5}\\\\v'=50\ cm/s

Hence , this is the required solution .

3 0
4 years ago
Which is not part of nuclear chemistry? A. Strong nuclear force B. Double-replacement reactions C. Radioactivity D. Nuclear deca
ziro4ka [17]

The correct choice is

B. Double-replacement reactions

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8 0
4 years ago
Read 2 more answers
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