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faust18 [17]
4 years ago
15

Determine how many grams of solute and solvent you would need to prepare 225 g of 11.9%

Chemistry
1 answer:
Tomtit [17]4 years ago
6 0

Answer:

m_{solute}=26.8g

Explanation:

Hello.

In this case, since the definition of by-mass percent is:

\%m/m=\frac{m_{solute}}{m_{solution}}*100\%

Whereas we know the percent as 11.9 % and the mass of the solution as 225g, so we compute the grams of solute as follows:

m_{solute}=\frac{\%m/m*m_{solution}}{100\%}\\ \\m_{solute}=\frac{11.9\%*225g}{100\%}\\ \\m_{solute}=26.8g

Best regards.

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