Question

Determine how many grams of solute and solvent you would need to prepare 225 g of 11.9%

Answer 1

Answer:

$m_{solute}=26.8g$

Explanation:

Hello.

In this case, since the definition of by-mass percent is:

$\%m/m=\frac{m_{solute}}{m_{solution}}*100\%$

Whereas we know the percent as 11.9 % and the mass of the solution as 225g, so we compute the grams of solute as follows:

$m_{solute}=\frac{\%m/m*m_{solution}}{100\%}\\ \\m_{solute}=\frac{11.9\%*225g}{100\%}\\ \\m_{solute}=26.8g$

Best regards.