Answer: False
Explanation:
Winds are named for the cardinal direction they blow from. Hence, a wind that <em>"blows towards the east"</em>, logically should <u>come from the west </u>and is called a <em>"west wind"</em>.
In thise sense, one of the best examples of this type of wind are the <em>Westerlies</em>, which are are prevailing winds that blow from the west at midlatitudes and have the characteristic that are stronger during winter and weaker during summer.
Therefore, the statement is false.
To solve this problem it is necessary to apply the principles of conservation of Energy in order to obtain the final work done.
The electric field in terms of the Force can be expressed as

Where,
F = Force
E= Electric Field
q = Charge
Puesto que el trabajo realizado es equivalente al cambio en la energía cinetica entonces tenemos que
KE = W
KE = F*d
In the First Case,

In Second Case,



The total energy change would be subject to,


Therefore the Kinetic Energy change of the charged object is 27.976J

Heat capacity of body 1 :

Heat capacity of body 2 :

it's given that, the the head capacities of both the objects are equal. I.e


Now, consider specific heat of composite body be s'
According to given relation :



[ since,
]




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A. Is the correct answer.
First of all, the formula for speed is;
Speed=distance/time
From the question, you have;
distance=7,200km
Time=9 hours
So that will be;
Speed=7200/9
When divided, you will have;
Speed=800
The unit for speed is km/hr or m/s. So that will be;
Speed=800km/hr
Hope that helped, have a nice day