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Neporo4naja [7]
3 years ago
14

Homogeneous mixtures

Chemistry
2 answers:
galina1969 [7]3 years ago
8 0

Explanation:

<h3>The mixture in which the particles of the components of solute and solvent are equally mixed is called homogeneous mixture. </h3>
Naily [24]3 years ago
6 0
A homogeneous mixture is simply any mixture that is uniform in composition throughout. as long as each substance is mixed in enough to be indistinguishable from the others, it is a homogeneous mixture.

examples: air, saline solution, most alloys, and bitumen
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Devise a temperature scale, abbreviated g, for which the magnitude of the ideal gas constant is 1.00 j g–1 mol–1 .
melisa1 [442]

The value of ideal gas constant (R) in Joule is 8.314 Joule Kelvin^{-1}mol^{-1}. Now the given expression is 1.00 J. gg^{-1}.mole^{-1}. Where the g represent the temperature. Thus the abbreviated g must have the value 8.314 to satisfy the original value. Thus the temperature scale will be 1 kelvin = 8.314 g. Now 1 kelvin  = -272.15°C or in terms of abbreviation of g we can write -272.15 °C = 8.314g, or, 1°C  = (-) \frac{8.314}{272.15}=0.030g. Thus the temperature scale of the g scale is 1 kelvin (K) = 8.314g and 1°C = 0.030 g.  

7 0
3 years ago
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Which nonmetal has the highest density?​
wolverine [178]

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3 0
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Propane burns in air to form water vapor and another gas. What is the volume of the water vapor at 500°C and 1 atm?​
kakasveta [241]

Answer:

253.85 L

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

C₃H₈ + 5O₂ —> 3CO₂ + 4H₂O

From the balanced equation above, 4 moles of water vapor were produced.

Finally, we shall determine the volume of the water vapor produced as follow:

Mole water vapor (n) = 4 moles

Pressure (P) = 1 atm

Temperature (T) = 500 °C = 500 °C + 273 = 773 K

Gas constant (R) = 0.821 atm.L/Kmol

Volume (V) =?

PV = nRT

1 × V = 4 ×0.0821 × 773

V = 253.85 L

Thus, the volume of water vapor obtained is 253.85 L

7 0
3 years ago
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