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2 years ago

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What happens to sodium sulphate in water

1 answer:

kirza4 [7]2 years ago

6 0

Answer:

It dissolves into the water

Na₂SO₄ + H₂O → 2Na₊_{aq} + SO₄²-_{aq}

Hope this helps :)

Have a great day !

5INGH

Explanation:

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What investigations never involve hypotheses?

marshall27 [118]

The correct answer is a descriptive investigation.

An investigation which does not involve hypotheses called descriptive investigation.
Hypotheses are termed as scientific hypotheses and require that one can test it. In hypothesis, previous observation can not satisfactorily be explained with an available scientific theory.
Working hypotheses are being proposed for further research.

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3 years ago

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Use the solubility curve above to answer the following: If I add 130 g of potassium iodide to 100 g of water at 10°C, how would

zhenek [66]

<span>solution of KI becomes saturated at 10 degrees when around 135-138g KI are added to 100 g of water, so it should be still unsaturated, A. unsaturated (although it is very close to saturation)</span>

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3 years ago

Calculate the masses of oxygen and nitrogen that are dissolved in of aqueous solution in equilibrium with air at 25 °C and 760 T

shtirl [24]

Explanation:

Let us assume that the volume of given aqueous solution is 7.5 L.

Therefore, according to Henry's law, the relation between concentration and pressure is as follows.

C = $\frac{P}{K_{h}}$

where, pressure (P) = 760 torr = 1 atm

According to Henry's law, constants for gases in water at $25^{o}C$ are as follows.

$p(O_{2})$ = 0.21 atm = 0.21 bar

$p(N_{2})$ = 0.78 atm = 0.78 bar

$K_{h}$ for $O_{2}$ = $7.9 \times 10^{2} bar/mol$

$K_{h}$ for $N_{2}$ = $1.6 \times 10^{3} bar /mol$

Since, 21% oxygen is present in air so, its mass will be 0.21 g. Similarly, 78% nitrogen means the mass of nitrogen is 0.78 g.

Therefore, concebtrations will be calculated as follows.

$C(O_{2}) = \frac{0.21}{7.9 \times 10^{2}} = 2.66 \times 10^-4 mol/L$

$C(N_2) = \frac{0.78}{1.6 \times 10^3} = 4.875 \times 10^-4 mol/L$

Now, we will calculate the number of moles as follows.

$n(O_{2}) = 7.5 \times 2.66 \times 10^-4 = 1.995 \times 10^-3$ mol

$n(N_2) = 7.5 \times 4.875 \times 10^-4 = 3.66 \times 10^-3$ mol

As the molar mass of $O_2$ = 32 g/mol

Hence, mass of oxygen will be as follows.

Mass of $O_2 = 32 \times 1.995 \times 10^-3 \times 1000$

= 63.84 mg

As the molar mass of $N_{2}$ = 28

Mass of $N_{2} = 28 \times 3.66 \times 10^-3$ = 102.5 mg

Thus, we can conclude that mass of oxygen is 63.84 mg and nitrogen is 102.5 mg.

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3 years ago

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At what temperature<br> (Celsius) will water change from a<br> liquid to solid?

fiasKO [112]

Answer:

0 degrees Celsius

Explanation:

6 0

2 years ago

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How much heat is released as the temperature of 25.2 grams of iron is decreased from 72.1°C to 9.8°C? The specific heat of iron

prisoha [69]

Answer:

$Q=-697.06\ J$

Negative sign says that release of heat.

Explanation:

The expression for the calculation of the heat released or absorbed of a process is shown below as:-

$Q=m\times C\times \Delta T$

Where,

$\Delta H$ is the heat released or absorbed

m is the mass

C is the specific heat capacity

$\Delta T$ is the temperature change

Thus, given that:-

Mass = 25.2 g

Specific heat = 0.444 J/g°C

$\Delta T=9.8-72.1\ ^0C=-62.3\ ^0C$

So,

$Q=25.2\times 0.444\times -62.3\ J=-697.06\ J$

Negative sign says that release of heat.

8 0

3 years ago