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DochEvi [55]
4 years ago
14

What are the partial and total vapor pressures of a solution obtained by mixing 35.8 g benzene, and 56.7 g toluene, at the vapor

pressure of the vapor pressure of C6H5CH3
Chemistry
1 answer:
Alla [95]4 years ago
6 0

Answer:

not sure, but you know what?

Explanation:

you are amazing! keep doing what youre doing!

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The following data were obtained in a kinetics study of the hypothetical reaction A + B + C → products. [A]0 (M) [B]0 (M) [C]0 (
Vladimir [108]

Answer:

B. First order, Order with respect to C = 1

Explanation:

The given kinetic data is as follows:

A + B + C → Products

     [A]₀     [B]₀    [C]₀       Initial Rate (10⁻³ M/s)

1.   0.4      0.4     0.2       160

2.  0.2      0.4      0.4       80

3.   0.6     0.1       0.2       15

4.   0.2     0.1       0.2        5

5.   0.2     0.2      0.4       20

The rate of the above reaction is given as:

Rate = k[A]^{x}[B]^{y}[C]^{z}

where x, y and z are the order with respect to A, B and C respectively.

k = rate constant

[A], [B], [C] are the concentrations

In the method of initial rates, the given reaction is run multiple times. The order with respect to a particular reactant is deduced by keeping the concentrations of the remaining reactants constant and measuring the rates. The ratio of the rates from the two runs gives the order relative to that reactant.

Order w.r.t A : Use trials 3 and 4

\frac{Rate3}{Rate4}= [\frac{[A(3)]}{[A(4)]}]^{x}

\frac{15}{5}= [\frac{[0.6]}{[0.2]}]^{x}

3 = 3^{x} \\\\x =1

Order w.r.t B : Use trials 2 and 5

\frac{Rate2}{Rate5}= [\frac{[B(2)]}{[B(5)]}]^{y}

\frac{80}{20}= [\frac{[0.4]}{[0.2]}]^{y}

4 = 2^{y} \\\\y =2

Order w.r.t C : Use trials 1 and 2

\frac{Rate1}{Rate2}= [\frac{[A(1)]}{[A(2)]}]^{x}[\frac{[B(1)]}{[B(2)]}]^{y}[\frac{[C(1)]}{[C(2)]}]^{z}

we know that x = 1 and y = 2, substituting the appropriate values in the above equation gives:

\frac{160}{80}= [\frac{[0.4]}{[0.2]}]^{1}[\frac{[0.4]}{[0.4]}]^{2}[\frac{[0.2]}{[0.4]}]^{z}

1 = (0.5)^{z}

z = 1

Therefore, order w.r.t C = 1

8 0
4 years ago
Solve using the distributive property <br>- 592×7 + 592 × 3​
marshall27 [118]

Answer:

= -592 (7+3)

= 592 ×10

= -5920

hope it helps u

Mark me brainless

8 0
3 years ago
Pls Help!
lilavasa [31]
B. Increases because the more liquid there,the more time is needed to boil it
3 0
3 years ago
Which BEST describes how an experiment should be designed?
vova2212 [387]

Answer:

form a hypothesis.

5 0
3 years ago
On Earth, Locations M and O are in areas that receive sunlight that is spread out. Which statement is most likely true about the
Ahat [919]

A-Locations M and O are at the poles.

Explanation:

Locations M and O are located at the poles because they receive sunlight that is spread out over a large surface area. The poles receive sunlight at an angle to the surface and it causes the rays of the sun to spread out in all direction.

  • At the equator, sunlight impinges directly on the surface and the solar radiation here is very much.
  • It is important to know that the sun is overhead directly at the equator.
  • The earth is tilted at an angle to sun and therefore, areas around the polar region will receive sunlight that is spread out in different directions over a large area.
  • Away from the pole, the equator is directly facing the sun and it receives direct sunlight.

Learn more:

solar radiation brainly.com/question/10940063

#learnwithBrainly

5 0
3 years ago
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