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forsale [732]
3 years ago
10

A 40 kg dog is sitting on top of a hillside and has a potential energy of 1,568 J. What is the height of the hillside?

Physics
1 answer:
beks73 [17]3 years ago
8 0
Potential Energy=M x G x  H
1,568=40 x 10 x H 
Now we isolate the H 
h=3.92m 

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What was the name of charles lindbergh’s single winged airplane for his solo flight across the atlantic?
aev [14]

Answer:

Spirit of St. Louis

Explanation:

Charles Lindbergh was known as a prolific aviator during the early twentieth century. He is well known for the flight he took from Long Island, New York, to Paris, France. It was a continuous flight across the Atlantic Ocean.

The plane he used was the Spirit of St. Louis which took more than 33 hours to complete the journey. It was the first successful flight of this kind. The airplane flew from Long Island on May 20 and landed in Paris on May 21.

4 0
3 years ago
An incident ray strikes a boundary at a 72.5-degree angle, resulting in an angle of refraction of 39.6 degrees. The index of ref
Finger [1]
Refractive index is the ration of sin i to sin r where i is the incident angle and r is the refraction angle. 
Therefore, refractive index = sin 79.5 / sin 39.6
                                           = 1.542
The refractive index may be given by the ratio of refractive index of medium 2 to refractive index of medium 1. 
Therefore, 1.542 = n/1.0003
                            n = 1.5425
                               ≈ 1.54
Medium 2 is sodium chloride, refractive index of 1.54

 
6 0
2 years ago
Read 2 more answers
Assume: Moving to the right is positive. A(n) 7.7 g object moving to the right at 22 cm/s makes an elastic head-on collision wit
krek1111 [17]

Answer:

Explanation:

We shall apply the formula for velocity in case of elastic collision which is given below

v₁ = (m₁ - m₂)u₁ /  (m₁ +  m₂)  + 2m₂u₂ / (m₁ +  m₂)

m₁ and u₁ is mass and velocity of first object , m₂ and  u₂ is mass and velocity of second object before collision and v₁ is velocity of first velocity after collision.

Here u₁ = 22 cm /s , u₂ = - 14 cm /s . m₁ = 7.7 gm , m₂ = 18 gm

v₁ = ( 7.7 - 18 ) x 22 / ( 7.7 + 18 )  + 2 x 18 x - 14 / ( 7.7 + 18 )

= - 8.817 - 19.6

= - 28.4 cm / s

5 0
3 years ago
8. An airplane is flying at 200 m/s when it touches the ground at the airport. It has a constant negative acceleration, and slow
Temka [501]

Answer:

Explanation:

Given

Initial velocity u = 200m/s

Final velocity = 4m/s

Distance S = 4000m

Required

Acceleration

Substitute the given parameters into the formula

v² = u²+2as

4² = 200²+2a(4000)

16 = 40000+8000a

8000a = 16-40000

8000a = -39,984

a = - 39,984/8000

a = -4.998m/s²

Hence the acceleration is -4.998m/s²

8 0
2 years ago
A small object of mass 3.82 g and charge -16.5 µC is suspended motionless above the ground when immersed in a uniform electric f
horrorfan [7]

Answer:

2271.16N/C  upward

Explanation:

The diagram well illustrate all the forces acting on the mass. The weight is acting downward and the force is acting upward in other to balance the weight.since the question says it is motionless, then indeed the forces are balanced.

First we determine the downward weight using

W=mg\\g=9.81m/s^{2}

Hence for a mass of 3.82g 0r 0.00382kg we have the weight to be

W=0.00382kg*9.81m/s^{2}

W=0.0375N

To calculate the electric field,

E=f/q\\E=0.0375/16.5*10^{-6} \\E=2271.16N/C

Since the charge on the mass is negative, in order to generate upward force, there must be a like charge below it that is  repelling it, Hebce we can conclude that the electric field lines are upward.

Hence the magnitude of the electric force is 2271.16N/C and the direction is upward

4 0
3 years ago
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