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3 years ago

Yo mismo no hablo español, así que espero que esto sea realmente legible--

2 answers:

6 0

Translation:
I do not speak spanish, so i hope this is legible—

What are the different ways the simulation shows that the equation balances visually.

For every reaction that’s balanced, indicates the total number of molecules ( the large coefficients ) in the table.

The reaction number total of molecules

The reactive side ( left ) The product ( right )

Make Ammonium

Water separated

Combust(?) Methane

Is the number of molecules totals in the left side of a balanced equation, is always the same number of molecules that totals on the right side of the equation? Explain your answers.

For every balanced reaction, indicated the total number of atoms ( the individual atoms ) in the table. Suggestion: this can require multiplying that subscript for the coefficient of some of the atoms.

Example: 2NH3: There’s 2 atoms of N and 6 atoms of H ( 2 x 3 ).

The reaction number of the total of atoms.

The reactive side ( left ) The product side ( right )

Make Ammonium

Separate Water

Combust Methane

Does the number of the atoms total to the left side of a equation balanced is always the same number of atoms total in the right side of the equation?

What strategy did you used when you played the game of the chemical equation of the equivalent? What atoms were more easier to start examining to try to balance the equations? Did it require trial and error ?

In the simulation, could you use the numbers that didn’t enter ( like 1/2 or 0.43 ) for the coefficients of a balanced equation?

Deffense [45]3 years ago

4 0

Answer:

what

Explanation:

You might be interested in

Uranium-236 is ____.

wolverine [178]

Answer: The correct answer is a.

Uranium-236 is intermediate nuclei created by fusion reactions an unstable isotopes of uranium created from four hydrogen atoms used in the H - bomb .

Following is the reaction involved in above process :

²³⁵U + ¹n = ²³⁶U = ¹⁴⁴Ba + ⁸⁹ Kr + 3¹n + 177 MeV

Here ,

²³⁵U = Fision Material ,

¹n = projectile ,

²³⁶U = Intermediate Nuclei

¹⁴⁴Ba and ⁸⁹ Kr = Fission product

Explanation:

hope it helps !

brainliest plzz :)))

3 0

3 years ago

Read 2 more answers

BH+ClO4- is a salt formed from the base B (Kb = 1.00e-4) and perchloric acid. It dissociates into BH+, a weak acid, and ClO4-, w

Len [333]

Answer:

The pH of 0.1 M BH⁺ClO₄⁻ solution is 5.44

Explanation:

Given: The base dissociation constant: $K_{b}$ = 1 × 10⁻⁴, Concentration of salt: BH⁺ClO₄⁻ = 0.1 M

Also, water dissociation constant: $K_{w}$ = 1 × 10⁻¹⁴

The acid dissociation constant ( $K_{a}$ ) for the weak acid (BH⁺) can be calculated by the equation:

$K_{a}. K_{b} = K_{w}$

$\Rightarrow K_{a} = \frac{K_{w}}{K_{b}}$

$\Rightarrow K_{a} = \frac{1\times 10^{-14}}{1\times 10^{-4}} = 1\times 10^{-10}$

Now, the acid dissociation reaction for the weak acid (BH⁺) and the initial concentration and concentration at equilibrium is given as:

Reaction involved: BH⁺ + H₂O ⇌ B + H₃O+

Initial: 0.1 M x x

Change: -x +x +x

Equilibrium: 0.1 - x x x

The acid dissociation constant: $K_{a} = \frac{\left [B \right ] \left [H_{3}O^{+}\right ]}{\left [BH^{+} \right ]} = \frac{(x)(x)}{(0.1 - x)} = \frac{x^{2}}{0.1 - x}$

$\Rightarrow K_{a} = \frac{x^{2}}{0.1 - x}$

$\Rightarrow 1\times 10^{-10} = \frac{x^{2}}{0.1 - x}$

$As, x$

$\Rightarrow 0.1 - x = 0.1$

$\therefore 1\times 10^{-10} = \frac{x^{2}}{0.1 }$

$\Rightarrow x^{2} = (1\times 10^{-10})\times 0.1 = 1\times 10^{-11}$

$\Rightarrow x = \sqrt{1\times 10^{-11}} = 3.16 \times 10^{-6}$

Therefore, the concentration of hydrogen ion: x = 3.6 × 10⁻⁶ M

Now, pH = - ㏒ [H⁺] = - ㏒ (3.6 × 10⁻⁶ M) = 5.44

Therefore, the pH of 0.1 M BH⁺ClO₄⁻ solution is 5.44

5 0

3 years ago

Given 1 cm3 = 1 mL A box has dimensions 2.0 cm x 4.0 cm x 8.0 cm.

svp [43]

Answer: 64

Explanation:

you just multiple the 3 numbers to get the answer (i’m in chemistry and just did this question lol)

5 0

3 years ago

A common radio wavelength observed coming from astronomical objects is 21 cm. What temperature is associated with this radiation

qaws [65]

Answer:

The temperature associated with this radiation is 0.014K.

Explanation:

If we assume that the astronomical object behaves as a black body, the relation between its wavelength and temperature is given by Wien's displacement law.

$\lambda_{max}=\frac{b}{T}$

where,

λmax is the wavelength at the peak of emission

b is Wien's displacement constant (2.89×10⁻³ m⋅K)

T is the absolute temperature

For a wavelength of 21 cm,

$T=\frac{b}{\lambda _{max} } = \frac{2.89 \times 10^{-3} m.K }{0.21m} =0.014K$

8 0

3 years ago

How many molecules are in 777.7 grams of water?

Alisiya [41]

to have the closest number rounded up

7 0

2 years ago