Translation: I do not speak spanish, so i hope this is legible—
What are the different ways the simulation shows that the equation balances visually.
For every reaction that’s balanced, indicates the total number of molecules ( the large coefficients ) in the table.
The reaction number total of molecules
The reactive side ( left ) The product ( right )
Make Ammonium
Water separated
Combust(?) Methane
Is the number of molecules totals in the left side of a balanced equation, is always the same number of molecules that totals on the right side of the equation? Explain your answers.
For every balanced reaction, indicated the total number of atoms ( the individual atoms ) in the table. Suggestion: this can require multiplying that subscript for the coefficient of some of the atoms.
Example: 2NH3: There’s 2 atoms of N and 6 atoms of H ( 2 x 3 ).
The reaction number of the total of atoms.
The reactive side ( left ) The product side ( right )
Make Ammonium
Separate Water
Combust Methane
Does the number of the atoms total to the left side of a equation balanced is always the same number of atoms total in the right side of the equation?
What strategy did you used when you played the game of the chemical equation of the equivalent? What atoms were more easier to start examining to try to balance the equations? Did it require trial and error ?
In the simulation, could you use the numbers that didn’t enter ( like 1/2 or 0.43 ) for the coefficients of a balanced equation?
Don’t currently have a calculator with me but just use Avogadros constant (A) 6.02x10^24, in the equation n=N/A. Lower case n being the number of mol and upper case being the number of molecules (given).
The simplest way to use the periodic table to identify an element is by looking for the element’s name or elemental symbol. The periodic table can be used to identify an element by looking for the element’s atomic number. The atomic number of an element is the number of protons found within the atoms of that element.
