1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
dalvyx [7]
3 years ago
15

Two tugboats pull a disabled supertanker. Each tug exerts a constant force of 1.8×106N , one an angle 11degrees west of north an

d the other an angle 11degrees east of north, as they pull the tanker a distance 0.83km toward the north. What is the total work they do on the supertanker?
Physics
1 answer:
sp2606 [1]3 years ago
7 0

Answer: 2,9 ×10¹⁰J.

Explanation:

1. The <em><u>work </u></em>is a measure of energy and is calculated as the product of the displacement times the parallel force to such displacement.

That means that the only components of the force that contribute to work are those that result parallel to the displacement.

2. Since it is given that the <em>two tugboats "pull the tanker a distance 0.83km toward the north"</em>, that is the displacement, and you have to calculate the net force toward the north.

3. <u>Tugboat #1</u>.

a) Force magnitude: F₁ = 1.8×10⁶N

b) Angle: α = 11° West of North

c) North component of the force F₁: Fy₁ = F₁cos(α) =  1.8×10⁶N  × cos(11°) = 1.77×10⁶N

4. <u>Tugboat #2</u>:

a) Force magnitude: F₂ = 1.8×10⁶N

b) Angle:  = 11° East of North

c) North component of the force F₂: Fy₂ = F₂cos(β) =  1.8×10⁶N  × cos(11°) = 1.77×10⁶N =

5. <u>Total net force, Fn</u>:

Fn = Fy₁ + Fy₂ = 1.77×10⁶N + 1.77×10⁶N = 3.54×10⁶N

6. <u>Work, W</u>:

Displacement, d = 0.83 km = 8,300 m

W = Fn×d = 3.54×10⁶N×8,300m = 29,000 ×10⁶J = 2,9 ×10¹⁰J

The answer is rounded to two significant figures because both data, Force and displacement, have two significant figures.

You might be interested in
find the mass of a ball on a roof 30 meters high, if the ball's gravitational potential energy is 58.8 joules
Sidana [21]
We are given the gravitational potential energy and the height of the ball and is asked in the problem to determine the mass of the ball. the formula to be followed is PE = mgh where g is the gravitational acceleration equal to 9.81 m/s^2. substituting, 58.8 J = m*9.8 m/s^2 * 30 m; m = 0.2 kg.
3 0
3 years ago
Read 2 more answers
A hungry lion is looking for food. It went 5 miles (mi) before it spotted a zebra to stalk. It took this lion 0.2 hours to get t
siniylev [52]
The lion covered 5 miles in 0.2 hours. With a quick division you can find the speed per hour: 5 / 0.2 = 25 mi/h
4 0
3 years ago
Read 2 more answers
Suppose a grower sprays (2.2x10^1) kg of water at 0 °C onto a fruit tree of mass 180 kg. How much heat is released by the water
Bond [772]

There is no temperature change which drives heat flow, thus no heat will be released by the water.

<h3>Heat released by the water when it freezes</h3>

The heat released by the water when it freezes is calculated as follows;

Q = mcΔФ

where;

  • m is mass of water
  • c is specific heat capacity of water
  • ΔФ is change in temperature = Фf - Фi

Initial temperature of water, Фi = 0 °C

when water freezes, the final temperature, Фf = 0 °C

Q = 22 x 4200 x (0 - 0)

Q = 0

Since there is no temperature change which drives heat flow, thus no heat will be released by the water.

Learn more about heat flow here: brainly.com/question/14437874

6 0
2 years ago
"Your are flying in Class C airspace and the controller says, "radar service is terminated". What should the transponder be set
EleoNora [17]

Answer:

Who knows

Explanation:

8 0
3 years ago
An excited 92 kg football player celebrates a touchdown by carelessly running straight into the goalpost at 9.4 m/s. He bounces
yKpoI14uk [10]

Answer:

i. 15.6 m/s

ii. I = 1.44 KNs

Explanation:

The impulse, I, on a body is the product of force applied on it and the time it acts.

i.e I = F x t

Impulse is sometimes expressed as the change in momentum of a body. It is measured in Ns.

i. mass, m, of the player = 92 kg

initial velocity of the player, u = 9.4 m/s

final velocity of the player, v = 6.2 m/s

Since he bounces back on hitting the pole, then the sign of initial and final velocities are of opposite sign.

So that,

change in velocity of the player = final velocity - initial velocity

                                          = 6.2 - (-9.4)

                                         = 6.2 + 9.4

                                         = 15.6 m/s

change in velocity of the player is 15.6 m/s

ii. Impulse, I = m(v - u)

                    = 92 x 15.6

                    = 1435.2

Impulse on the player is 1.44 KNs.

7 0
3 years ago
Other questions:
  • Which statement describes why scientific notation is useful? It makes very small numbers into whole numbers. It converts fractio
    9·2 answers
  • What distance formula
    15·1 answer
  • A 350-kg sailboat has an acceleration of 0.62 m/s2 at a angle of 64 degrees north of east find the magnitude and direction of th
    9·1 answer
  • A dentist uses a concave mirror (focal length 2.5 cm) to examine some teeth. If the distance from the object to the mirror is 1.
    5·1 answer
  • In which part of the ear is the sound wave converted into electrical impulse
    15·2 answers
  • You want to arrive at your friend's house by 5pm her house is 240 kilometers away if your average speed will be 80km on the trip
    7·1 answer
  • Consider shining a laser through a small circular hole. The resulting diffraction pattern will look like a bullseye - a series o
    13·1 answer
  • A turtle is moving at a speed of 1.5 m/s for a time of 120 s. What is the distance the turtle travels?
    11·2 answers
  • 30pts!!!06.01 Simple Harmonic Motion Lab: Virtual Lab Simulation
    12·2 answers
  • Compare and contrast camera obscura with what you know about modern digital photography, including cell phones.
    10·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!