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mr Goodwill [35]
3 years ago
9

HELPP MEEE 15 POINTS!

Chemistry
1 answer:
Mademuasel [1]3 years ago
5 0
The answer is A.

During any chemical change the total mass doesn’t changes. Whatever the total mass of starting materials was present the same mass of ending products is present in a chemical reaction.

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Help please I’ll give you brainless
Helen [10]
• Liquid at room temperature
•Gas at room temperature
• Argon has approximately the same solubility in water as oxygen and is 2.5 times more soluble in water than nitrogen. Argon is colorless, odorless, nonflammable and nontoxic as a solid, liquid or gas. Argon is chemically inert under most conditions and forms no confirmed stable compounds at room temperature.
5 0
3 years ago
A can contains a gas with a volume of 86 mL at 30oC. What is the volume in the can if it is heated to 65oC?
Ber [7]

Answer:

New volume of gas = 95.93 ml (Approx)

Explanation:

Given:

Old volume of gas = 86 ml

Old temperature = 30°C = 30 + 273 = 303 K

New temperature = 65°C = 65 + 273 = 338 K

Find:

New volume of gas

Computation:

V1T2 = V2T1

(86)(338) = (V2)(303)

New volume of gas = 95.93 ml (Approx)

8 0
3 years ago
What does a mole of iron weigh
r-ruslan [8.4K]

As the atomic mass of iron is 55.847u

We say that it is the mass of one mole of iron.

By formula it can be find by

No.of mole=mass in g/molar mass

Mass in gram = no.of mole x molar mass

No.of mole =1

Molar mass = 55.847g

Mass in gram = 1x55.847

= 55.847g of Fe

3 0
3 years ago
12<br> -4<br> si<br> -8<br> -4<br> 0<br> 4<br> 8<br> -4
sergeinik [125]

Answer:

hulaan mo nlng

Explanation:

dko den alam ehh

6 0
3 years ago
What is the temperature of CO2 gas if the average speed (actually the root-mean-square speed) of the molecules is 750 m/s?
erastova [34]

Answer:

992.302 K

Explanation:

V(rms) = 750 m/s

V(rms) = √(3RT / M)

V = velocity of the gas

R = ideal gas constant = 8.314 J/mol.K

T = temperature of the gas

M = molar mass of the gas

Molar mass of CO₂ = [12 + (16*2)] = 12+32 = 44g/mol

Molar mass = 0.044kg/mol

From

½ M*V² = 3 / 2 RT

MV² = 3RT

K = constant

V² = 3RT / M

V = √(3RT / M)

So, from V = √(3RT / M)

V² = 3RT / M

V² * M = 3RT

T = (V² * M) / 3R

T = (750² * 0.044) / 3 * 8.314

T = 24750000 / 24.942

T = 992.302K

The temperature of the gas is 992.302K

Note : molar mass of the gas was converted from g/mol to kg/mol so the value can change depending on whichever one you use.

3 0
3 years ago
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