Alright. Start by plugging in -3 for d. There are absolute value signs on the outside, so it negates the negative and makes it just 3. I hope this helps you.
From,
Am3865211
Step-by-step explanation:
4:16
No it's ok no need to thank me, it's my duty to help someone like you
Given:
The given function is:

To find:
The value of x that is in the domain.
Solution:
Domain is the set of input values.
We have,

We know that the square root is defined for non negative values. So,



Thus, the domain of the given function is all real number that are greater than or equal to 7.
In the given options 0, -3, 6 are less than 7 but 8 in option A is the only value that is greater than 7. So,
is in the domain of the given function.
Therefore, the correct option is A.
<span>Given the two end of the diameter of the circle, we are able to compute the center of the circle as 0.5*[(-1,3)+(7,-7)]=(3,-2). The radius of the circle is 0.5*sqrt[(-1-7)^2+(3+7)^2]=sqrt(41). Therefore the equation of the circle is (x-3)^2+(y+2)^2=41.</span>