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2 years ago

6

A slide with an image 4cm×2cm is placed at a distance of 10 cm behind a converging lens and a clear image is formed on a screen

1.1 m from the slide. the size of the image on the screen is

1 answer:

pav-90 [236]2 years ago

7 0

Answer:

44cm x 22cm

Explanation:

u= 10 cm

v= 1.1 cm

m=v/u= 1.1/10

m=11

hence the size of the image.

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A feather, a tennis ball, and a bowling ball are dropped from a high tower on

Vlada [557]

Answer:

In the absence of air resistance. I think no. D ) The bowling ball.

<em><u>Hope</u></em><em><u> this</u></em><em><u> helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

7 0

2 years ago

Help me please, i need it fast

s2008m [1.1K]

Answer:

2) C. (x - 3)² + (y + 2)² = 25

5) x² + y² - 8x - 16y + 54 = 0

6) x² + y² - 10x - 12y + 36 = 0

Explanation:

2)

center of circle = 3, -2

x1, y1

end point of circle = 7, 1

x2, y2

the equation of a circle is Pythagorean theorem

x² + y² = r² (where r is the radius of a circle)

distance between points

(x2 - x1)² + (y2 - y1)² = r²

(7 - 3)² + (1 - (-2))² = r²

r² = 25

therefore the equation to the circle is

(x - 3)² + (y + 2)² = 25

=========================================

5)

write the general form of a circle with the center (4,8)

and containing the point (-1, 7)

distance between points

(x2 - x1)² + (y2 - y1)² = r²

(-1 - 4)² + (7 - 8)² = r²

r² = 26

(x - 4)² + (y - 8)² = 26

(x - 4)(x - 4) + (y - 8)(y - 8) = 26

x² - 8x + 16 + y² - 16y + 64 -26 = 0

x² + y² - 8x - 16y + 54 = 0

=========================================

6)

find the general form of a circle with center (5,6)

and tangent to the y-axis.

center (5,6)

h, k

radius = r²

r = 5

(x - h)² + (y - k)² = r²

(x - r)² + (y - k)² = r²

(x - 5)(x - 5) + (y - 6)(y - 6) = r²

x² - 10x + 25 + y² - 12y + 36 = 25

x² + y² - 10x - 12y + 36 = 0

=========================================

8 0

2 years ago

Which type wire should be used to increase resistance

8_murik_8 [283]

Nichrome wire. That's the stuff that toasters are made from. The resistance is pretty high, considering the diameter. 1 meter is at about the same guage as that listed below for copper is about 96 ohms.

Most of the time you are trying to use wire with the least resistance.

A meter of copper has a listed resistance of 0.024 ohms / meter. The wire is a 19 guage wire which makes it pretty thin.

===============

I'm not sure what you are asking. If want the resistance of something in terms of what would increase the resistance of the same material for both calculations then

Rule 1: It you decrease the wire diameter, you increase the resistance

Rule 2: If you increase the length of the wire, you increase the resistance.

Both rules assume you are using something like copper.

7 0

2 years ago

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You cross two pure tall (TT) plants with two pure short (tt) plants and produce four offspring. Which of the following statement

grandymaker [24]

All will have a dominant trait I can't see the following statments

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2 years ago

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The drawing shows a large cube (mass = 28.6 kg) being accelerated across a horizontal frictionless surface by a horizontal force

MrRissso [65]

Answer:

P= 454.11 N

Explanation:

Since P is the only horizontal force acting on the system, it can be defined as the product of the acceleration by the total mass of the system (both cubes).

$P= (M+m)*a\\a = \frac{P}{28.6 +4.3}\\a = \frac{P}{32.9}$

The friction force between both cubes (F) is defined as the normal force acting on the smaller cube multiplied by the coefficient of static friction. Since both cubes are subject to the same acceleration:

$F = m * a*\mu \\F= 4.3*0.710*\frac{P}{32.9}\\F=3.053*\frac{P}{32.9}$

In order for the small cube to not slide down, the friction force must equal the weight of the small cube:

$3.053*\frac{P}{32.9} = 4.3 * g\\\\P = \frac{4.3*9.8*32.9}{3.053} \\P= 454.11 N$

The smallest magnitude that P can have in order to keep the small cube from sliding downward is 454.11 N

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3 years ago