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lubasha [3.4K]
3 years ago
7

A swimmer uses her feet to push off the wall and the wall exerts the same force back on her. The force exerted by the wall on th

e swimmer is called ___________
a. action force
b. friction
c. gravity
d. reaction force
Physics
1 answer:
Likurg_2 [28]3 years ago
7 0

Answer: Option d

Explanation:

According to Newton's third law, for every force "P" that is applied on an object there is a force -P that has the same maginitud that "P" and opposite direction.

In other words "for every action there is an  equal and opposite reaction"

For example, if Object D applies a force "P" on an object B, then object B will make a force -P on object D.

This force is called the reaction force.

Therefore when the swimmer pushes the wall, then the wall pushes the swimmer with a force of the same magnitude that is called the reaction force.

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Find the magnitude of the sum of two vectors; A is 5 km , and B is 7 , when the angle btween them is 120
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Answer: 6.24 km

Explanation:

Given

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A box of oranges which weighs 83 N is being pushed across a horizontal floor. As it moves, it is slowing at a constant rate of 0
otez555 [7]

The given question is incomplete. The complete question is as follows.

A box of oranges which weighs 83 N is being pushed across a horizontal floor. As it moves, it is slowing at a constant rate of 0.90 m/s each second. The push force has a horizontal component of 20 N and a vertical component of 25 N downward. Calculate the coefficient of kinetic friction between the box and the floor.

Explanation:

The given data is as follows.

    F_{1} = 20 N, F_{2} = 25 N, a = -0.9 m/s^{2}

             W = 83 N

         m = \frac{83}{9.81}

             = 8.46

Now, we will balance the forces along the y-component as follows.

       N = W + F_{2}

           = 83 + 25 = 108 N

Now, balancing the forces along the x component as follows.

       F_{1} - F_{r} = ma

        20 - F_{r} = 8.46 \times (-0.9)

             F_{r} = 7.614 N

Also, we know that relation between force and coefficient of friction is as follows.

             F_{r} = \mu \times N

          \mu = \frac{F_{r}}{N}

                    = \frac{7.614}{108}

                    = 0.0705

Thus, we can conclude that the coefficient of kinetic friction between the box and the floor is 0.0705.

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