Answer:
a) Batteries and fuel cells are examples of galvanic cell
b) Ag-cathode and Zn-anode
c) Cell notation: Zn(s)|Zn²⁺(aq) || Ag⁺(aq)|Ag(s)
Explanation:
a) A galvanic cell is an electrochemical cell in which chemical energy is converted to electrical energy. The chemical reaction which drives a galvanic cell is a redox reaction i.e. a reduction-oxidation process.
A typical galvanic cell is composed of two electrodes immersed in a suitable electrolyte and connected via a salt bridge. One of the electrodes serves as a cathode where reduction or gain of electrons takes place. The other half cell functions as an anode where oxidation or loss of electrons occurs. Batteries and fuel cells are examples of galvanic cells.
b) The nature of the electrode that will serve as an anode or cathode depends on the value of the standard reduction potential (E⁰) of that electrode. The electrode with a higher or more positive the value of E⁰ serves as the cathode and the other will function as an anode.
In the given case, the E⁰ values from the standard reduction potential table are:
E⁰(Zn/Zn2+) = -0.763 V
E°(Ag/Ag+)=+0.799 V
Therefore, Ag will be the cathode and Zn will be the anode
c) In the standard cell notation, the anode half cell is written on the left followed by the salt bridge '||' and finally the cathode half cell to the right.
Zn(s)|Zn²⁺(aq) || Ag⁺(aq)|Ag(s)
Answer:
Wavelength of light is 600 nm
Explanation:
Given
Distance between the first order maximum and the tenth order maximum of a double-slit pattern = 18 mm
Separation between the slits = 0.15 mm
Distance of screen from the slits = 50 cm
Wavelength
nm
Answer: The calculated volume measures the side of the cube to get the volume. An indirect measurement of volume measures the displacement of a liquid by a solid.
Explanation:
Volume is the amount of the space occupied by an object. Volume can be used to measure the amount of the space occupied by the solid, liquid and gas.
When the direct measurement is not possible then the indirect measurement is used by taking the small part that object to calculate the whole part of that.
The limitations of the calculated and indirect volume measurement are as follows,
The calculated volume measures the side of the cube to get the volume. An indirect measurement of volume measure the displacement of a liquid by a solid. For example, the volume of the liquid is displaced by the sponge is not equal to the volume of the sponge.
Answer:
Mass=3,height=50 and time=15,g=10,P=?
P=mgh/t....which is 3×10×50=1500/15=100Watts
