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finlep [7]
3 years ago
6

3 questions 35 points

Physics
2 answers:
bearhunter [10]3 years ago
4 0
The answer to question one would be Ethier A or D and the answer to question number 2 is B friction the answer to question number 3 is B kinetic energy
Ksivusya [100]3 years ago
4 0

Answer:

i think d.b.d

Explanation:

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Which of the following describes the products of a chemical reaction? A. The original materials B. The substances that are chang
lianna [129]

The products of a chemical reaction are the substances that are changed and the chemicals on the right side of a chemical equation. The correct options are B and C.

<h3>What is chemical reaction?</h3>

The chemical reaction  is the reaction between two reactants which led to the formation of products.

The products are substances which forms after reaction. The reactants are the substances which are original materials.

The reactants lie on the left side and products lie on the right side of the reaction.

Thus, the correct options are B and C.

Learn more about chemical reaction.

brainly.com/question/22817140

#SPJ1

7 0
2 years ago
. A laser beam shines along the surface of a block of transparent material (see Fig. E33.8). Half of the beam goes straight to a
Neporo4naja [7]

Answer:

n = 1,875

Explanation:

The speed of light in vacuum is constant (c) and in a material medium it is

          v = d / t

The refractive index of a material is defined by

         n = c / v

         

Let's look for the speed of light in the material, in general the length that light travels is known, this value is high, x = 1, when we place a block on the road, a small amount is lengthened by the length of the block, which in general is despised

These measurements are made on a digital oscilloscope that allows to stop the signals and measure their differences, that is, the zero is taken when the first ray arrives and the time for the second ray is measured,

         

         v = d / t

         v = 1 / 6.25 10⁻⁹

         v = 1.6 10⁸ m / s

we calculate the refractive index

        n = 3 10⁸ / 1.6 10⁸

        n = 1,875

6 0
3 years ago
Q12. How big is a Moon? How big is a Mars? What is therefore the weight of the person from Q11 on the Moon? What is the person's
shutvik [7]

Answer:

The moon is 1,079.4 mi.

Mars is 2,106.1 mi

Multiply your weight by the moon's gravity relative to earth's, which is 0.165. Solve the equation. In the example, you would obtain the product 22.28 lbs. So a person weighing 135 pounds on Earth would weigh just over 22 pounds on the moon

Being that Mars has a gravitational force of 3.711m/s2, we multiply the object's mass by this quanitity to calculate an object's weight on mars. So an object or person on Mars would weigh 37.83% its weight on earth.

Explanation:

~Hope this helps

7 0
3 years ago
A constant force of 8N acting on an object displaces it through a distance of 3.0 m in the direction of force. Calculate work-do
sweet-ann [11.9K]

\blue{\bold{\underline{\underline{Answer:}}}}

  • \green{\tt{Work\:done=24\:J}}

\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}

\green{\underline{\bold{Given :}}} \\  \tt: \implies Constant \: force(F) = 8 \: N \\  \\ \tt: \implies Displacement(s) = 3 \: m \\  \\ \red{\underline{\bold{To \: Find : }}} \\  \tt:  \implies Work \: Done(W.D) = ?

• <u>According to given question</u> :

\green{ \star} \tt \:  \theta \:  = 0 \degree \:  \:  \:  \: (Angle \: between \: force \: and \: displacement) \\  \\  \bold{As \: we \: know \: that} \\  \tt:  \implies Work \: Done = FS \: cos  \: \theta \\  \\  \tt:  \implies Work \: Done = 8 \times 3 \times cos \:0 \degree \\  \\ \green{ \circ} \tt \: cos  \: 0 \degree = 1  \\  \\  \tt:  \implies Work \: Done =24 \times 1 \\  \\   \green{\tt:  \implies Work \: Done =24 \: J}

5 0
3 years ago
Two cars are traveling on a desert road. After 5.0 seconds they are side by side at the next telephone pole.The distance between
stira [4]
The question looks incomplete, but according to the information given above seem like they have <span>identical journeys.
</span>a. the displacement of car A - <span> 65.5 m 
</span>b. the displacement of car B  - <span>65.5 m
c. average velocir</span>y of A  65.5 / 5 = 13.1 m/s
d. the average velocity of car B  has the same. 
8 0
3 years ago
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