Kinetic energy = (1/2)*mass*velocity^2
KE = (1/2)mv^2
KE = (1/2)(478)(15)^2
KE = 53775J
<span>As the temperature goes down, the chaotic motion (velocity) of atoms start decreasing. If the temperature hits the absolute zero (which, in reality, is impossible to achieve), the atoms of the body would freeze, making the body still and stiff. One thing to note here is that the atoms do not get destroyed when the temperature reaches the absolute zero. That is the reason why the object can still be seen when it is at absolute zero.</span>
A because centrifugal is to velocity to how slow or fast something is and centrifugal has expresssed as ac=v2 / r (1)<span />
Answer:
0.28802
2.57162 W
14.28 W
53.55 W
6.07142 W
Explanation:
R = 280Ω
L = 100 mH
C = 0.800 μF
V = 50 V
ω = 10500rad/s
For RLC circuit impedance is given by

Power factor is given by

The power factor is 0.28802
The average power to the circuit is given by

The average power to the circuit is 2.57162 W
Power to resistor

Power to resistor is 14.28 W
Power to inductor

Power to the inductor is 53.55 W
Power to the capacitor

The power to the capacitor is 6.07142 W
Answer:
5.88×10⁸ W
Explanation:
Power = change in energy / time
P = mgh / t
P = (m/t) gh
P = (1.2×10⁶ kg/s) (9.8 m/s²) (50.0 m)
P = 5.88×10⁸ W