First, we determine the moles of Mg(NO₃)₂ present:
moles = mass / Mr
= 46.5 / (24 + 2 x (14 + 16 x 3))
= 0.4 mole
Each mole of Mg(NO₃)₂ contains 2 moles of Nitrogen atoms.
Moles Nitrogen = 0.4 x 2
= 0.8 mole
Answer:For jewellery and ornaments, gold, platinum and silver are being used.
For building purposes, iron and steel can be used.Iron and aluminium are used as utensils.
The thermometer uses mercury and helps to monitor the temperature.
The insulation wires are made of aluminium.
Aluminium foils are being used as wrappers for food.In sweets, a silver foil is being used.
To avoid rusting, zinc is used for galvanizing.In vehicles, iron is being used.
For making cable wires, copper is being used.
Explanation:
Answer:
The methyl group will already be present
Explanation:
You want to make 1-methyl-4-nitrobenzene.
The question is, "Do I start with the methyl group on the ring and then nitrate, or do I start with the nitro group on the ring and then add the methyl group?"
The methyl group is activating and ortho, para directing.
The nitro group is deactivating and meta directing.
You want a para-substituted product, so you choose to nitrate toluene, as in the reaction scheme below.
1) Chemical equation:
Mg + I2 ---> Mg I2
2) molar ratios
1 mol Mg : 1 mol I2 : 1 mol Mg I2
3) Calculate the number of moles of Mg in 48 grams
Atomic mass of Mg: 24.3 g/mol
number of moles = mass in grams / atomic mass = 48 g / 24.3 g/mol = 1.975 mol Mg
4) Use a proportion with the molar ratios
1 mol I2 / 1 mol Mg = x / 1.975 mol Mg =>
=> x = 1 mol I2 * 1.975 mol Mg / 1 mol Mg = 1.975 mol I2
5) Convert 1.975 mol I2 to grams
molar mass of I2 = 2 * 126.9 g/mol = 253.8 g/mol
mass = number of moles * molar mass = 1.975 mol * 253.8 g/mol = 501.255 g
Answer: 501 grams
I don’t really know this but I think
