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victus00 [196]
2 years ago
8

State what is meant by a gravitational potential at point A is -1·70 × 109 J kg-1.​

Physics
1 answer:
alex41 [277]2 years ago
8 0

Answer:

The energy stored in a body due to either it's position or change in shape is called gravitational potential energy.

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The study of ____ is called kinematics
weqwewe [10]
Motaion would be it have a good day
7 0
3 years ago
Read 2 more answers
If a boomerang is thrown 20 m in a straight line and returns exactly at the same spot from which it is thrown, what is its displ
Anettt [7]

Answer:

C) 0m

Explanation:

Since at the end of the day, it was not displaced

Displacement ti's a vector quantity

8 0
3 years ago
A football player with a mass of 88 kg and a speed of 2.0 m/s collides head-on with a player from the opposing team whose mass i
Ket [755]

Answer:

Speed of another player, v₂ = 1.47 m/s

Explanation:

It is given that,

Mass of football player, m₁ = 88 kg

Speed of player, v₁ = 2 m/s

Mass of player of opposing team, m₂ = 120 kg

The players stick together and are at rest after the collision. It shows an example of inelastic collision. Using the conservation of linear momentum as :

m_1v_1+m_2v_2=(m_1+m_2)V

V is the final velocity after collision. Here, V = 0 as both players comes to rest after collision.

v_2=-\dfrac{m_1v_1}{m_2}

v_2=-\dfrac{88\ kg\times 2\ m/s}{120\ kg}

v_2=-1.47\ m/s

So, the speed of another player is 1.47 m/s. Hence, this is the required solution.

7 0
3 years ago
I have no idea of how to approach this problem
nataly862011 [7]

Answer:

p=1

Explanation:

Well me know that v=m/s

and that a=m/s^2

so

(m/s)^{2} = (m/s^2)(x^p)\\\\(m^2/s^2)/(m/s^2)=x^p\\\\m^2s^2/ms^2=x^p\\\\(m^2/m)(s^2/s^2)=x^p\\\\m=x^p\\\\p=1

Note: We don't take into account 2 because it's a scalar, it doesn't have units so it doesn't add anything to the equation.

4 0
3 years ago
i)Distinguish between different methods of charging. ii) You are provided with a positively charged gold leaf electroscope. Stat
AleksAgata [21]

Answer:

Explanation:

On rubbing a glass rod with silk, the electrons from the glass rod get transferred to the silk. The silk now has an excess of electrons and so is negatively-charged. On the other hand, the glass rod is deficient in electrons and hence is positively-charged.

In the above case, the silk undergoes negative electrification.

Now, when the positively charged glass rod is touched on the disc of a negatively charged gold leaf electroscope, the electrons shifts towards rod, hence amount of charge on gold leaves decreases and the divergence between the gold leaves decreases as unlike charges attract each other.

Hence, the divergence decreases when a glass rod rubbed with silk is brought near the disc of negatively charged electroscope.

hope it helps pls mark me as brainliest

6 0
3 years ago
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