Well, what I would do is divide it into two shapes. Cut off the bottom part to make two separate quadrilaterals, and you'd have a square with sides of x. So the area would be x^2. Then, for the remaining piece (rectangle), add the x from the square bit to 5 for one side, and the other side would be x. So you'd have 5x * x, which equals 5x^2. Add the two separate area's together to get the total area, which would give you 6x^2. Hope that helped! :)
Answer:
4a²-9
Step-by-step explanation:
(2a+3)(2a-3) = (2a)²-3² {<em>Difference</em><em> </em><em>of</em><em> </em><em>two</em><em> </em><em>squares</em><em>}</em>
= 4a²-9
Answer:
-6i
Step-by-step explanation:
Complex roots always come in pairs, and those pairs are made up of a positive and a negative version. If 6i is a root, then its negative value, -6i, is also a root.
If you want to know the reasoning, it's along these lines: to even get a complex/imaginary root, we take the square root of a negative value. When you take the square root of any value, your answer is always "plus or minus" whatever the value is. The same thing holds for complex roots. In this case, the polynomial function likely factored to f(x) = (x+8)(x-1)(x^2+36). To solve that equation, you set every factor equal to zero and solve for the x's.
x + 8 = 0
x = -8
x - 1 = 0
x = 1
x^2 + 36 = 0
x^2 = -36 ... take the square root of both sides to get x alone
x = √-36 ... square root of an imaginary number produces the usual square root and an "i"
x = ±6i
A ) 5x^3 - 6x^4
B ) 11x^4 - 13x^3
C ) 14^x3 - 2x^4
D ) 2x^4 - 12x^3
E) 5x^4 - 3x^3
I believe this is all right!
