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aleksklad [387]
4 years ago
13

In many cases, large trucks move more slowly up hills than small cars. What do you think is the reason for this

Physics
2 answers:
barxatty [35]4 years ago
7 0
T&hey are heavier I believe and need a bigger engine to make it
hope i helped
Have a great day
BabaBlast [244]4 years ago
5 0
The trucks are larger then cars and need to go slow so they have traction between the tires and the road when there moving large things.
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Chemicals in the air can combine with rain to produce acid rain, which is harmful to the environment. Which of these is most lik
irinina [24]
Hi there!

Normal rain has a pH between 5.0 and 5.5, which is slightly acidic on the pH scale. Acid rain on the other hand has an average pH of 4.0, much more acidic than your average rain.

Therefore, the most likely pH of acid rain would be 4.0.
7 0
3 years ago
7. A car travels a certain distance with a speed of
goblinko [34]
Let distance be x.

Time in going, t 1 = x/50

Time in coming, t 2 = x/40

Total time T = x/40 +x/50 = 9x/200

Average speed = total distance/ total time

=( x+x)/(9x/200)= 2x ×200/9x = 400/9 = 44.44 km/h
5 0
3 years ago
In which of the following situations is consciousness NOT involved?
schepotkina [342]
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6 0
4 years ago
If the pressure is 100,000 Pa, R is 8.314, the temperature is 300 K, and the number of moles of gas (n) is 100, what is the volu
djyliett [7]
We can solve the problem by using the ideal gas equation:
pV=nRT
where
p is the pressure of the gas
V is the volume of the gas
n is the number of moles of the gas
R is the gas constant
T is the absolute temperature of the gas

For the gas in our problem, we have:
p=100000 Pa
R=8.314 J mol^{-1} K^{-1}
T=300 K
n=100

If we rearrange the equation and we put these numbers into it, we find the volume of the gas:
V= \frac{nRT}{p}= \frac{(100)(8.314)(300)}{100000}=2.49 m^3
4 0
3 years ago
A 0.537-kg basketball is dropped out of a window that is 5.88 m above the ground. The ball is caught by a person whose hands are
Monica [59]

Answer:

a) 20.54 J

b) 30.97 J

c) 10.43 J

d) -20.54 J

Explanation:

m = Mass

g = Acceleration due to gravity = 9.81 m/s²

h = Height

W=mgh\\\Rightarrow W=0.537\times 9.81\times (5.88-1.98)\\\Rightarrow W=0.537\times 9.81\times 3.9\\\Rightarrow W=20.54\ J

Work done by the ball's weight is 20.54 J

W=mgh\\\Rightarrow W=0.537\times 9.81\times (5.88)\\\Rightarrow W=30.97\ J

Gravitational potential energy of the basketball, relative to the ground, when it is released is 30.97 J

W=mgh\\\Rightarrow W=0.537\times 9.81\times (1.98)\\\Rightarrow W=10.43\ J

Gravitational potential energy of the basketball, relative to the ground, when it is released is 10.43 J

Change in gravitational potential energy

\Delta U=10.43-30.97=-20.54\ J

Change in gravitational potential energy is given by -20.54 J

4 0
4 years ago
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