Question

A capacitor is charged to 8.0×10−4 C , then discharged by connecting a wire between the two plates. 35us after the discharge begins, the capacitor still holds 14 % of its original charge.
What was the average current during the first 35us of the discharge?

Answer 1

Answer:

The average current is 19.567 A

Solution:

As per the question:

Charge, Q = $8.0\times 10^{- 4}\ C$

Time, t = $35\times 10^{- 6}\ s$

Now,

We know that current is constituted by the rate of transfer of the charge per unit time. Thus we can write:

I = $\frac{Q}{t}$                 (1)

Now, the charge that was transferred is 86 % of the original value.

Therefore,

We replace Q by 0.86Q in eqn (1):

I = $\frac{0.86\times 8.0\times 10^{- 4}}{35\times 10^{- 6}} = 19.657\ A$