If we double the mass of the sun, what would happen to the gravitational force between the sun and earth?

Physics

1 answer:

Sphinxa [80]3 years ago

4 0

It would increase
because the force is directly proportional to the Value of masses given

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The two forces in each pair may have different physical origins (for instance, one of the forces could be due to gravity, and it

kap26 [50]

Answer:

b)False

Explanation:

This is the false statement .The two forces in each pair could not have different physical origins.

The two pair of forces have same origin.It can not be possible that one is electric force and other one is gravity force or friction force.

We know that magnitude of electric force is much smaller than the friction force .So they can not be in pair form.

Answer is b) False

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3 years ago

Jay kicks a soccer ball Upward at an angle of 45 with a velocity of 20 m/s landing 2.8 seconds later

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Answer:hello what are we to do

Explanation:

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Which sentence from the article supports the idea that the visible spectrum is more limited in marine animals than humans? A Mos

lidiya [134]

Most marine bioluminescence is blue-green, which is easier to see in the deep ocean

Explanation:

As per science, Emission and production of light by a living organism is defined as Bioluminescence. Bioluminescence occurs widely in marine animals whereas it is triggered by a physical disturbance is seen by humans, such as a moving boat hull or waves.

Throughout the water column bioluminescent organisms live and bioluminescence is extremely common in deep sea which shows that visible spectrum is more limited to marine animals than humans.

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3 years ago

Two satellites are in circular orbits around the earth. The orbit for satellite A is at a height of 403 km above the earth’s sur

BARSIC [14]

Answer:

$v_A=7667m/s\\\\v_B=7487m/s$

Explanation:

The gravitational force exerted on the satellites is given by the Newton's Law of Universal Gravitation:

$F_g=\frac{GMm}{R^{2} }$

Where M is the mass of the earth, m is the mass of a satellite, R the radius of its orbit and G is the gravitational constant.

Also, we know that the centripetal force of an object describing a circular motion is given by:

$F_c=m\frac{v^{2}}{R}$

Where m is the mass of the object, v is its speed and R is its distance to the center of the circle.

Then, since the gravitational force is the centripetal force in this case, we can equalize the two expressions and solve for v:

$\frac{GMm}{R^2}=m\frac{v^2}{R}\\ \\\implies v=\sqrt{\frac{GM}{R}}$

Finally, we plug in the values for G (6.67*10^-11Nm^2/kg^2), M (5.97*10^24kg) and R for each satellite. Take in account that R is the radius of the orbit, not the distance to the planet's surface. So $R_A=6774km=6.774*10^6m$ and $R_B=7103km=7.103*10^6m$ (Since $R_{earth}=6371km$ ). Then, we get:

$v_A=\sqrt{\frac{(6.67*10^{-11}Nm^2/kg^2)(5.97*10^{24}kg)}{6.774*10^6m} }=7667m/s\\\\v_B=\sqrt{\frac{(6.67*10^{-11}Nm^2/kg^2)(5.97*10^{24}kg)}{7.103*10^6m} }=7487m/s$