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Irina18 [472]
3 years ago
12

Draw a mechanism for this reaction. 5-hydroxypentanoic acid forms 2-oxanone in the presence of acid. draw all missing reactants

and/or products in the appropriate boxes by placing atoms on the canvas and connecting them with bonds. add charges where needed. electron flow arrows should start on an atom or a bond and should end on an atom, bond, or location where a new bond should be created.
Chemistry
1 answer:
Licemer1 [7]3 years ago
3 0

Answer: -

The first step involves protonation of the carbonyl oxygen.

After protonation, the Alcohol oxygen now attacks the carbon of the carbonyl.

Thus a six membered ring is formed with 5 carbon atoms and 1 oxygen atom. The 1st position carbon atom has 2 OH groups.

One of these gets again protonated.

This leaves as water. With the loss of the H+, there results a carbonyl at 1 position.

Thus 5-hydroxypentanoic acid forms a lactone or 2-oxanone in presence of acid.

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Note that the complete question is given below:

Part A

Identify the chemical symbols corresponding to each element Drag the appropriate labels to their respective targets.

View Available Hint(s)

Element

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