Agar is extracted from an algae (agarophytes, <span>belong to the </span>Rhodophyta (red algae) phylum, <span>primarily from the </span>genera Gelidium<span> and </span><span>Gracilaria</span>).
Agar <span>or </span>agar-agar is a jelly-like substance. Agar is the mixture of two components, agaropectin (D-glucuronic acid and pyruvic acid) and <span>the polysaccharide agarose.</span>
The given question is incomplete. The complete question is as follows.
Citrate synthase catalyzes the reaction
Oxaloacetate + acetyl-CoA 
citrate + HS-CoA
The standard free energy change for the reaction is -31.5 kJ*mol^-1
(
a) Calculate the equilibrium constant for this reaction a 37degrees C
Explanation:
(a). It is known that
, relation between change in free energy (
) of a reaction and equilibrium constant (K) is as follows.
where, T = temperature in Kelvin
The given data is as follows.
T = 310 K, 
(as 1 kJ = 1000 J)
Now, putting the given values into the above formula as follows.
ln K = 
= 
ln K = 12.22
K = antilog (12.22)
= 
Therefore, we can conclude that value of equilibrium constant for the given reaction is .
Answer:
From the atmosphere to the hydrosphere by diffusion.
From the atmosphere to the biosphere by photosynthesis.
From the atmosphere to the geosphere by rainfall.
Explanation:
Carbon atom goes from the atmosphere to the hydrosphere by the process of diffusion because there is high concentration of carbondioxide present in the atmosphere. The carbon atom goes from the atmosphere to the biosphere by the process of photosynthesis in plants which uses carbondioxide gas as a raw material in the process for the preparation of organic compounds such as glucose. The carbon atom goes from the atmosphere to the geosphere with the help of rain. When carbondioxide gas react with water in the atmosphere, carbonic acid is formed and comes to the ground through rainfall.
Answer:
See explanation
Explanation:
Anode;
Sn(s) ------> Sn^2+(aq) + 2e
Cathode;
Mn^2+(aq) + 2e ------> Mn(s)
The minimum voltage required to drive the reaction is the cell voltage. The cell voltage is obtained from;
E°cell= E°cathode - E°anode
E°cell= -1.19 - (-0.14)
E°cell= -1.05 V
