Which of the aqueous solution does not conduct electricity ? 1.Ca(NO3)2 / 2.CH3NH2/ 3.CH3OH/ 4.CH3COOH

Chemistry

1 answer:

bezimeni [28]3 years ago

8 0

For an aqueous solution to conduct electricity, ions must be present in solution.

This means soluble salts will conduct electricity. Also, since acids and bases have ions in solution, they could also conduct electricity. Option 1 is a soluble salt. Options 2 and 4 are base and acid respectively. Option 3, though soluble in water, exist as a molecule, therefore its solution cannot conduct electricity.

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$CH_{3}COOH \ \textless \ ---\ \textgreater \ H^{+} + CH_{3}COO^{-}$

In this case pH value of the solution is necessary to calculate the concentration but it's not given here so pH = 2.88 (looked it up)

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Change $moldm^{-3}$ -0.001 +0.001 +0.001

Equilibrium $moldm^{-3}$ $x$ - 0.001 0.001 0.001


Since the $k_{a}$ value is so small, the assumption
$[CH_{3}COOH]_{initial} = [CH_{3}COOH]_{equilibrium}$ can be made.

$k_{a} = [tex]= 1.8*10^{-5} = \frac{[H^{+}][CH_{3}COO^{-}]}{[CH_{3}COOH]} = \frac{0.001^{2}}{x}$

Solve for x to get the required concentration.

note: 1.)Since you need the answer in 2SF don&t round up values in the middle of the calculation like I've done here.

2.) The ICE (Initial, Change, Equilibrium) table may come in handy if you are new to problems of this kind

Hope this helps!

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Answer: 1. 3.914 × ^10-4 | 2. 4.781 × ^10-1

Explanation:

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