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Marrrta [24]
4 years ago
6

An object of mass m slides down an incline with angle 0.

Physics
2 answers:
juin [17]4 years ago
8 0

Answer:

B). F_N - mgcos\theta = 0

Explanation:

As we know that the force on the mass "m" which slides along the inclined plane is along the inclined surface

So it must have accelerated along that surface only

So we can write the equation for force along the inclined plane as

F_{net} = ma

now if we wish to find net force perpendicular to the plane then we can say that it must be zero

Because perpendicular to the plane the net force on the given mass must be zero as it is not accelerating along that direction

So here we can say

F_{net} = 0

so we have

F_N - mgcos\theta = 0

MAVERICK [17]4 years ago
5 0
<h3>Answer</h3>

B)

FN - mgcosФ = 0

<h3>Explanation</h3>

Given the mass of an object, forces that will be acting on it are as following

  • Force due to gravity (weight) of an object
  • The Normal force (the perpendicular force from that the inclined surface exerts on the object)
  • Any frictional forces (due to static friction or kinetic friction, if applicable) along the incline
  • The corresponding force component along the incline (downhill force due to gravity)

Force due to gravity = -mgcosΔ

Normal force = fN

Frictional force = -f

force applied forward = mgsinΔ

Horizontal force = mgsinΔ - f

vertical force = fN -  mgcosΔ

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A 1.11 kg piece of aluminum at 78.3 c is put into a glass with 0.210 kg of water at 15.0
ValentinkaMS [17]

M = mass of aluminium = 1.11 kg

c_{a} = specific heat of aluminium = 900

T_{ai} = initial temperature of aluminium = 78.3 c

m = mass of water = 0.210 kg

c_{w} = specific heat of water = 4186

T_{wi} = initial temperature of water = 15 c

T = final equilibrium temperature = ?

using conservation of heat

Heat lost by aluminium = heat gained by water

M c_{a} (T_{ai} - T) = m c_{w} (T - T_{wi} )

(1.11) (900) (78.3 - T) = (0.210) (4186) (T - 15)

T = 48.7 c

7 0
3 years ago
You have a string with a mass of 0.0133 kg. You stretch the string with a force of 8.89 N, giving it a length of 1.97 m. Then, y
Kazeer [188]

Answer:

(i) The wavelength is 0.985 m

(ii) The frequency of the wave is 36.84 Hz

Explanation:

Given;

mass of the string, m = 0.0133 kg

tensional force on the string, T = 8.89 N

length of the string, L = 1.97 m

Velocity of the wave is:

V = \sqrt{\frac{F_T}{M/L} } \\\\V = \sqrt{\frac{8.89}{0.0133/1.97} } \ = 36.29 \ m/s

(i) The wavelength:

Fourth harmonic of a string with two nodes, the wavelength is given as,

L = 2λ

λ = L/2

λ = 1.97 / 2

λ = 0.985 m

(ii) Frequency of the wave is:

v = fλ

f = v / λ

f = 36.29 / 0.985

f = 36.84 Hz

3 0
4 years ago
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tankabanditka [31]

Answer:

The blade of sharpener is made up of iron. Iron is a magnetic material because of this pencil sharpener gets attracted by the poles of a magnet although the body is made up of plastic.

5 0
3 years ago
Wo siblings are arguing over what way to pull a 10 kg wagon. Boris wants to pull it to the right. Boris puts 220 N of force on t
Mrrafil [7]

Answer:

a) Then net force acting on the wagon  30 [N] in a negative direction to the left

b)Acceleration of the wagon 3 m/s² in a negative direction to the left

Explanation:

The coordinates x and y show the positive direction in x-axis ( to the right) and negative direction to the left. In north-south direction positive y values are to the north and negative values to the south

The free-body diagram shows 4 forces acting

In y-axis:

The weight ( P = m*g =  10 [kg]*9,8 [m/s²] = 98 [N] negative

Normal reaction force  Fn = P = 98 [N]  positive ( surface is frictionless)

∑Fy = 0     P - Fn = 0     P = Fn  = 98 [N]

In x-axis:

Boris pulling force to the right (positive ) 220 [N]

Natasha pulling force to the left ( negative) 250 [N]

∑Fx = m*a

220 [N] - 250 [N]  = 10 Kg * a                      [N] = Kg * m /s²

-30 [kg*m/s²]  = 10 * Kg * a

-30/10  =  - 3  m/s²  = a

Sign (-) means the direction of acceleration vector is to the left (the same direction of the movement )

Then net force acting on the wagon  30 [N] in negative direction to the left

Acceleration of the wagon 3 m/s² in negative direction to the left

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dimaraw [331]

Cellular respiration

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3 years ago
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