Rutherford's experiment<span> utilized positively charged alpha particles (He with a +2 charge) which were deflected by the dense inner mass (nucleus). The conclusion that could be formed from this result was that </span>atoms<span> had an inner core which contained most of the mass of an </span>atom<span> and was positively charged.</span>
Answer: 7.38 km
Explanation: The attachment shows the illustration diagram for the question.
The range of the bomb's motion as obtained from the equations of motion,
H = u(y) t + 0.5g(t^2)
U(y) = initial vertical component of velocity = 0 m/s
That means t = √(2H/g)
The horizontal distance covered, R,
R = u(x) t = u(x) √(2H/g)
Where u(x) = the initial horizontal component of the bomb's velocity = 287 m/s, H = vertical height at which the bomb was thrown = 3.24 km = 3240 m, g = acceleration due to gravity = 9.8 m/s2
R = 287 √(2×3240/9.8) = 7380 m = 7.38 km
The lightbulb that carries more current will be the 25W bulb.
<h3>How to explain the information?</h3>
It should be noted that an electric current simply means the stream of charged particles that move through an electrical conductor or space.
In this case, it should be noted that the power is the same for both bulbs. Therefore, the 25W bulb will have the higher resistance so that it will have lower power.
Therefore, the lightbulb that carries more current will be the 25W bulb.
Learn more about current on:
brainly.com/question/1100341
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Vaporization of a sample of liquid is a phase transition from the liquid phase to the gas phase.
Answer:
energy required=-energy lost
energy lost=change in kinetic energy
EL=1/2 mv^2
