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rodikova [14]
3 years ago
7

A high-jumper clears the bar and has a downward velocity of - 5.00 m/s just before landing on an air mattress and bouncing up at

1.0 m/s. The mass of the high-jumper is 60.0 kg. What is the magnitude and direction of the impulse that the air mattress exerts on her
Physics
1 answer:
Jobisdone [24]3 years ago
8 0

-- As she lands on the air mattress, her momentum is (m v)

Momentum = (60 kg) (5 m/s down) = 300 kg-m/s down

-- As she leaves it after the bounce,

Momentum = (60 kg) (1 m/s up) = 60 kg-m/s up

-- The impulse (change in momentum) is

Change = (60 kg-m/s up) - (300 kg-m/s down)

Magnitude of the change = <em>360 km-m/s </em>

The direction of the change is <em>up /\ </em>.

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4 years ago
Which items in this image are electrically conductive? Check all that apply.
balu736 [363]

Answer: a and d

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3 years ago
Use the data provided to calculate the gravitational potential energy of each cylinder mass. Round your answers to the nearest t
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Answer: 14.7kJ, 29.4kJ, 44.1kJ

Explanation:

<em>The gravitational potential energy is the energy that a body or object possesses, due to its position in a gravitational field.  </em>

<em />

In the case of the Earth, in which the gravitational field is considered constant, the value of the gravitational potential energy U_{p} will be:  

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Where m is the mass of the object, g=9.8m/s^{2} the acceleration due gravity and h=500m the height of the object.  

Knowing this, let's begin with the calculaations:

For m=3kg

U_{p}=(3kg)(9.8m/s^{2})(500m)  

U_{p}=14700J=14.7kJ  

For m=6kg

U_{p}=(6kg)(9.8m/s^{2})(500m)  

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6 0
3 years ago
A 1500 kg car traveling east at 40 km/hr turns a corner and speeds up to a velocity of 50 km/hr due north. What is the change in
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Answer:

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momentum p₁ = mV₁

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Magnitude of change

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