Answer:
Pressure gas A
using boyles law

=
V2
V2 = 717ml + 179 ml
= 896ml
∴
= 2.50 × 717ml/896ml
= 2.0 bar
Pressure B
P2 = 4.30 bar× 179ml/896ml
= 0.859bar
ptotal =
+
= 2.0 bar + 0.859 bar
= 2.859 bar
Explanation: Using Daltons law of partial pressure,the pressure is independently of each other when the gas is exerted.where we can use daltons law to find the pressure of each gas separately when it expands into the total volume in two containers.
The answer is C, a catalyst. This is due to the fact that catalysts are substances that can be used to speed up a reaction by lowering the activation energy required. However, the catalyst itself is not actually used up during the reaction.
The pH of the diluted HCl solution is 1.3.
Explanation:
Given:
The concentrated HCl solution of 8.0 M. The 1.5 mL of 8.0 M HCl is diluted with water to 250 mL volume.
To find:
The pH of the diluted HCl solution.
Solution
- The concentration of the HCl solution before dilution =

- The volume of the HCl solution taken for dilution =

- The concentration of the HCl solution after dilution =

- The volume of the HCl solution after dilution =

Using the Dilution equation:

The concentration of diluted HCl solution = 0.048 M

In the 1 M solution of HCl, there are 1 M of hydrogen ion, then the concentration of hydrogen ions in 0.048 M of HCl will be:
![[H^+]=1\times 0.048M=0.048 M](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3D1%5Ctimes%200.048M%3D0.048%20M)
The pH of the diluted HCl solution :
![pH=-\log [H^+]\\=-\log [0.048M]=1.18 \approx 1.3](https://tex.z-dn.net/?f=pH%3D-%5Clog%20%5BH%5E%2B%5D%5C%5C%3D-%5Clog%20%5B0.048M%5D%3D1.18%20%5Capprox%201.3)
The pH of the diluted HCl solution is 1.3.
Learn more about the dilution equation here:
brainly.com/question/24546169?referrer=searchResults
brainly.com/question/1199928?referrer=searchResults
Answer:
Explanation:
A 30.0g sample of O2 at standard temperature and pressure (STP) would occupy what volume in liters
PV =nRT
at STP P= 1atm. T= 273 K
n is the number of moles. O2 has a molar mass of 32.
30 gm of O2 is 30/32= 0.94 =n
PV = nRT
at STP: P= 1 atm, T=273 K, R is always 0.082 for P in atm and T in K
SO
1 X V = 0.94 X 0.082 X 273
using high school freshman algebra,
V= 0.94 X 0.082 X 273 = 21L
using high school algebra I,
V=