2 years ago

How many genders are there?

Physics

2 answers:

Dvinal [7]2 years ago

8 0

Answer:2

Explanation:

marta [7]2 years ago

8 0

Answer:

There are more than two genders, even though in our society the genders that are most recognized are male and female (called the gender binary) and usually is based on someone's anatomy (the genitals they were born with).

In America, you may identify as whatever you please so, therefore, there is technically infinite genders

I identify as an attack helicopter

You might be interested in

When the frequency of an electromagnetic wave increases, its energy

OverLord2011 [107]

The energy stays the same

8 0

2 years ago

Read 2 more answers

A certain tuning fork vibrates at a frequency of 215 Hz while each tip of its two prongs has an amplitude of 0.832 mm. (a) What

Marysya12 [62]

Explanation:

It is given that,

Frequency of vibration, f = 215 Hz

Amplitude, A = 0.832 mm

(a) Let T is the period of this motion. It is given by the following relation as :

$T=\dfrac{1}{f}$

$T=\dfrac{1}{215}$

$T=4.65\times 10^{-3}\ s$

(b) Speed of sound in air, v = 343 m/s

It can be given by :

$v=f\times \lambda$

$\lambda=\dfrac{v}{f}$

$\lambda=\dfrac{343\ m/s}{215\ Hz}$

$\lambda=1.59\ m$

Hence, this is the required solution.

5 0

3 years ago

The nucleus is found in the center of an atom options: True False

AfilCa [17]

It’s true all the way. It’s true

8 0

2 years ago

Read 2 more answers

Why might political parties prefer closed primaries to open primaries

sweet [91]

In a closed primary, only voters registered with a given party can vote in that party's primary.

5 0

3 years ago

En un m.A.S. La amplitud tiene un valor de 10 centimetros y el periodo es de 2 segundos calcular el valor de la velocidad de 0.8

Ivanshal [37]

Answer:

v1=18.46m/s

v2=29.8cm/s

Explanation:

We know that

$A=10cm\\T=2s$

the equation of the motion is

$x=Acos(\omega t)\\$

we can calculate w by using

$\omega=\frac{2\pi}{T}=\frac{2\pi}{2}=\pi$

Hence, we have that

$x=10cm*cos(\pi t)\\$

the speed will be

$v=-\omega*Asin(\omega t)\\|v(0.8)|=|\pi*10cm*sin(\pi *0.8)|=18.46\frac{cm}{s}\\|v(1.4)|=|\pi*10cm*sin(\pi *1.4)|=29.8\frac{cm}{s}$

hope this helps!

6 0

3 years ago