Temperature is a measure of the energy of molecules and energy is related to speed.
<span>The water in a pot is heated by convection. The water on the bottom will warm up and rise toward the surface and the cooler water will then sink to the bottom where it will be heated. </span>
<span>Oxygen will form ionic bonds with nitrogen. The others will not by themselves. </span>
<span>A high pH is indicative of a basic solution. HCl and H2SO4 are both strong acids and will result in a lower (more acidic) pH. Water is the standard. KOH is a strong base and will increase the pH. </span>
<span>An acidic solid will lower the pH of a solution. pH measures the number of hydrogen ions and a lower pH will mean that there are more H+ ions, but the solid could just have reacted with the OH- to cause the pH to decrease</span>
Answer:
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Explanation:
I dont know because I am a noob ant study
Answer:
0.45 seconds
Explanation:
Letting the value of g = 10 m/s/s
final velocity (v) = 0 m/s (since the egg will come to rest at the maximum height)
initial velocity(u) = 4.5 m/s
acceleration = -10 m/s/s (since the gravity is acting against the egg)
time = t seconds
From the first equation of motion:
<em>v = u + at</em>
<em>0 = 4.5 + (-10)t</em>
<em>t = -4.5 / -10</em>
t = 0.45 seconds
Answer:
The number of oxygen molecules in the left container greater than the number of hydrogen molecules in the right container.
Explanation:
Given:
Molar mass of oxygen, 
Molar mass of hydrogen, 
We know ideal gas law as:
where:
P = pressure of the gas
V = volume of the gas
n= no. of moles of the gas molecules
R = universal gs constant
T = temperature of the gas
∵
where:
m = mass of gas in grams
M = molecular mass of the gas
∴Eq. (1) can be written as:
as: 
So,
Now, according to given we have T,P,R same for both the gases.
∴The molecules of oxygen are more densely packed than the molecules of hydrogen in the same volume at the same temperature and pressure. So, <em>the number of oxygen molecules in the left container greater than the number of hydrogen molecules in the right container.</em>
The force applied by the competitor is littler than the heaviness of the barbell. At the point when the barbell quickens upward, the power applied by the competitor is more prominent than the heaviness of the barbell. When it decelerates upward, the power applied by the competitor is littler than the heaviness of the barbell.
