Answer:
B, B (decreases, a clockwise)
Explanation:
Finally, the switch on the electromagnet is reopened. The magnitude of the external magnetic flux through the wire loop <u>decreases</u>, and there is <u>a clockwise</u>, current induced in the loop (as seen from the left).
45) B) Vaporizing water at its boiling point
46) D) There is no change in temperature
47) B) Molecules must be pulled apart
48) D) Steam at 100 C
Hope this helps!
Answer:
(a). The horizontal and vertical components are and
(b). The horizontal and vertical components of the rocket's impact velocity is 150 m/s and 259.8 m/s.
Explanation:
Given that,
Angle = 60°
Speed = 300 m/s
(a). We need to draw the vector representing the rocket's impact and its components
Using given data
The components of rocket's impact
The horizontal component is
The vertical component is
(b). We need to calculate the horizontal and vertical components of the rocket's impact velocity
Using horizontal and vertical components
The horizontal component is
Put the value into the formula
The vertical component is
Put the value into the formula
Hence, (a). The horizontal and vertical components are and
(b). The horizontal and vertical components of the rocket's impact velocity is 150 m/s and 259.8 m/s.
Answer:
In odd nuclei, the left out proton or neutron will contribute to the spin of the nucleus.
Explanation:
The meaning of odd nuclei is atomic mass is odd.
A=odd number.
A=Z+n
Here, Z is proton either it will odd or n will odd which is neutron.
Now according to the shell model the left out proton or neutron will contribute to the spin and parity.
For example,
Take the case of isotope of nitrogen-15.
Here Z is 7, and n is 8 will not contribute in spin.
Now, for Z=7.
Here,
and, L=1.
Fort parity,
Put the value of L.
Parity will be -1.
Now, spin will be
.
Answer:
10 minutes
Explanation:
Given:
Given:Speed of bus excluding stoppages =54 km/h
Speed of bus including stoppages = 45 km/h
To calculate: Minutes/per hour the bus stopped = ?
Distance covered by bus without stopping =54 km/h
Distance covered by bus with stopping =45 km/h
Due to stoppages it could
9km (54-45km) less
Time taken to cover 9 km=?
time \: taken \: = \frac{distane}{speed }timetaken=
speed
distane
Distance=9km
Speed = 54km/h.
Substituting given values on the above formula we get,
time \: taken \: = \frac{9}{54} hour = \frac{1}{6} hour \:timetaken=
54
9
hour=
6
1
hour
=10 minutes
Hence,the correct answer is 10 minutes.