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3 years ago

A horseshoe weighs 8.2 ounces. The nails make up 0.2 of that weight. What is the weight of the horseshoe without the nails

Mathematics

1 answer:

Serga [27]3 years ago

6 0

I think it would be 8

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10.222 in a fraction

liq [111]

5111/500 or 10 111/500

8 0

3 years ago

if you could generate energy by fusing the hydrogen in solution a, how much of the solution would you need to generate the elect

iogann1982 [59]

Answer:

We know that:

Energy released by fusion of hydrogen in 1 liter of solution A = 7.6x10^10 J

Energy used daily in a certain family home = 3x10^4 J

(you did not write the units, so i suppose that are the same in both cases)

Then, if x is the number of liters of solution A used, the energy produced will be:

E(x) = x*7.6x10^10 J

And we want this equal to 3x10^4

then:

E(x) = x*7.6x10^10 J = 3x10^4 j

now we solve this for x.

x = (3x10^4 j)/(7.6x10^10 j) = 3.9x10^-7

Then you need to use 3.9x10^-7 L of solution a.

4 0

4 years ago

Use the fundamental theorem of calculus to find the area of the region between the graph of the function x^5 + 8x^4 + 2x^2 + 5x

BaLLatris [955]

Answer:

The area of the region is 25,351 $units^2$ .

Step-by-step explanation:

The Fundamental Theorem of Calculus: if $f$ is a continuous function on $[a,b]$ , then

$\int_{a}^{b} f(x)dx = F(b) - F(a) = F(x) | {_a^b}$

where $F$ is an antiderivative of $f$ .

A function $F$ is an antiderivative of the function $f$ if

$F^{'}(x)=f(x)$

The theorem relates differential and integral calculus, and tells us how we can find the area under a curve using antidifferentiation.

To find the area of the region between the graph of the function $x^5 + 8x^4 + 2x^2 + 5x + 15$ and the x-axis on the interval [-6, 6] you must:

Apply the Fundamental Theorem of Calculus

$\int _{-6}^6(x^5+8x^4+2x^2+5x+15)dx$

$\mathrm{Apply\:the\:Sum\:Rule}:\quad \int f\left(x\right)\pm g\left(x\right)dx=\int f\left(x\right)dx\pm \int g\left(x\right)dx\\\\\int _{-6}^6x^5dx+\int _{-6}^68x^4dx+\int _{-6}^62x^2dx+\int _{-6}^65xdx+\int _{-6}^615dx$

$\int _{-6}^6x^5dx=0\\\\\int _{-6}^68x^4dx=\frac{124416}{5}\\\\\int _{-6}^62x^2dx=288\\\\\int _{-6}^65xdx=0\\\\\int _{-6}^615dx=180\\\\0+\frac{124416}{5}+288+0+18\\\\\frac{126756}{5}\approx 25351.2$

3 0

3 years ago

Is 5,000 cm greater than 5 m

ANTONII [103]

That is false 5,000cm is bigger you got this way to go

3 0

3 years ago

Read 2 more answers

X+y=20 linear and proportional

FromTheMoon [43]

It is linear since but it isn't proportional

8 0

3 years ago