I’m not sure, but I think A. from an internal engine reservoir
2Ag2S + 2H2O—>4Ag+2H2S+O2
The reactants are silver sulphide (Ag2s) and water (H2O)
Answer:
(R)-but-3-en-2-ylbenzene
Explanation:
In this reaction, we have a very <u>strong base</u> (<em>sodium ethoxide</em>). This base, will remove a hydrogen producing a double bond. We know that the reaction occurs through an <u>E2 mechanism</u>, therefore, the hydrogen that is removed must have an <u>angle of 180º</u> with respect to the leaving group (the "OH"). This is known as the <u>anti-periplanar configuration</u>.
The hydrogen that has this configuration is the one that placed with the <u>dashed bond</u> (<em>red hydrogen</em>). In such a way, that the base will remove this hydrogen, the "OH" will leave the molecule and a double bond will be formed between the methyl and the carbon that was previously attached to the "OH", producing the molecule (R) -but-3- en-2-ylbenzene.
See figure 1
I hope it helps!
The number of moles of H atoms in 15.2 grams of pure ice is 0.850 moles
The number of moles of O atoms in 15.2 grams of pure ice is 13.50 moles
<h3>What is an atom?</h3>
An atom is a smallest indivisible particle of a chemical element that is capable of independent existence.
- Pure ice contains the H2O molecules and the molar mass of H2O is 18.02 g/mol
Using the relation:
- number of moles = mass/molar mass
The number of moles of H2O = 15.2 grams/18.02 g/mol
number of moles of H2O = 0.8435 moles
If the atomic mass of H and O are as follow:
- the atomic mass of H atom is = 1.00784 g/mol
- the atomic mass of O atom is = 15.999 g/mol
Then:
the number of H atoms in 15.2 grams of pure ice = mass of H atom × molar mass of H2O.
the number of H atoms = 0.8435 mol × 1.00784 g/mol
the number of H atoms = 0.850 moles
the number of O atoms in 15.2 grams of pure ice = 0.8435 mol × 15.999 g/mol
the number of O atoms = 13.50 moles
Learn more about atoms here:
brainly.com/question/25832904
