C) alternately increase and decrease
Answer:
64 kPa
Explanation:
The pressure exerted by a force on a surface is given by
where
p is the pressure
F is the force
A is the area on which the force is exerted
In this problem, let's call:
F = the weight of the performer, which is the force
A = the area of 1 stilt
At the beginning, the performer is standing on both stilts, so the area on which he exerts pressure is 2A. So the pressure is
(1)
Later, he stands on one stilt only. The force exerted is still the same (his weight), however, the area is now reduced to A; therefore, the new pressure is
which is twice the value calculated in (1); so, the new pressure is
Answer:
6.69 m/s
4.483 m
1.42s
Explanation:
Given that:
Initial Velocity, u = 0
Final velocity, v =?
Acceleration, a = 35m/s²
1.) using the relation :
v² = u² + 2as
v² = 0 + 2(35) * 64*10^-2m
v² = 70 * 0.64
v = sqrt(44.8)
v = 6.693
v = 6.69 m/s
B.) height from the ground, h0 = 2.2
How high ball went , h:
Using :
v² = u² + 2as
Upward motion, g = - ve
0 = 6.69² + 2(-9.8)*(h - 2.2)
0= 6.69² - 19.6(h - 2.2)
44.7561 + 43.12 - 19.6h = 0
19.6h = 44.7561 - 43.12
h = 87.8761 / 19.6
h = 4.483 m
C.)
vt - 0.5gt² = h - h0
6.69t - 0.5(9.8)t²
6.69t - 4.9t² = 1.83 - 2.2
-4.9t² + 6.69t + 0.37 = 0
Using the quadratic equation solver :
Taking the positive root:
1.4185 = 1.42s
Yes I believe it would I think the answer is D
<span>The answer is Multichannel, single phase. </span>Machine breakdown and repair in a twelve machine factory having three repair mechanics would develop a Multichannel, single phase queuing system line structure concerning machine breakdowns. It is <span>Multiple
servers, one phase of service.</span>
