The car in the figure travels at a constant speed along the road shown. Draw vector showing its acceleration at the point C if t
he acceleration at point A is drawn. The lengths of your vectors should correspond to the magnitudes of the accelerations.
Draw the vector Ac with its tail at point C. The orientation and exact length of your vector will be graded.
Draw the vector Ac with its tail at point C. The orientation and exact length of your vector will be graded.
1 answer:
Answer:
The vector form is as shown in the attachment
Explanation:
The figure as shown in the diagram, indicates that the car is moving along the road at a constant speed. Centripetal acceleration comes into play for an object moving in a circular motion at uniform speed. The centripetal acceleration is the acceleration experienced by an object while in uniform circular motion.
Mathematically from centripetal acceleration; a = v2/r
The equation shows that there is an inverse relationship between the acceleration and the radius of curvature as such the radius of curvature at the point A will be more than the radius of curvature at the point C, this shows that the centripetal acceleration at point C will be more than the centripetal acceleration at point A.
The attachment shows the figure and the representation in vectorial form.
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Answer:
When they are connected in series
The 50 W bulb glow more than the 100 W bulb
Explanation:
From the question we are told that
The power rating of the first bulb is
The power rating of the second bulb is
Generally the power rating of the first bulb is mathematically represented as
Where is the normal household voltage which is constant for both bulbs
So
substituting values
Thus the resistance of the second bulb would be evaluated as
From the above calculation we see that
This power rating of the first bulb can also be represented mathematically as
This power rating of the first bulb can also be represented mathematically as
Now given that they are connected in series which implies that the same current flow through them so
This means that
So when they are connected in series
This means that the 50 W bulb glows more than the 100 \ W bulb
The total flux through the cylinder is zero.
In fact, the electric flux through a surface (for a uniform electric field) is given by:
where
E is the intensity of the electric field
A is the surface
is the angle between the direction of E and the perpendicular to the surface, whose direction is always outwards of the surface.
We can ignore the lateral surface of the cylinder, since the electric field is parallel to it, therefore the flux through the lateral surface of the cylinder is zero (because and
).
On the other two surfaces, the flux is equal and with opposite sign. In fact, on the first surface the flux will be
where r is the radius, and where we have taken since the perpendicular to the surface is parallel to the direction of the electric field, so
. On the second surface, however, the perpendicular to the surface is opposite to the electric field, so
and
, therefore the flux is
And the net flux through the cylinder is