The car in the figure travels at a constant speed along the road shown. Draw vector showing its acceleration at the point C if t
he acceleration at point A is drawn. The lengths of your vectors should correspond to the magnitudes of the accelerations.
Draw the vector Ac with its tail at point C. The orientation and exact length of your vector will be graded.
Draw the vector Ac with its tail at point C. The orientation and exact length of your vector will be graded.
1 answer:
Answer:
The vector form is as shown in the attachment
Explanation:
The figure as shown in the diagram, indicates that the car is moving along the road at a constant speed. Centripetal acceleration comes into play for an object moving in a circular motion at uniform speed. The centripetal acceleration is the acceleration experienced by an object while in uniform circular motion.
Mathematically from centripetal acceleration; a = v2/r
The equation shows that there is an inverse relationship between the acceleration and the radius of curvature as such the radius of curvature at the point A will be more than the radius of curvature at the point C, this shows that the centripetal acceleration at point C will be more than the centripetal acceleration at point A.
The attachment shows the figure and the representation in vectorial form.
You might be interested in
Before the engines fail , the rocket's horizontal and vertical position in the air are
and its velocity vector has components
After , its position is
and the rocket's velocity vector has horizontal and vertical components
After the engine failure , the rocket is in freefall and its position is given by
and its velocity vector's components are
where we take .
a. The maximum altitude occurs at the point during which :
At this point, the rocket has an altitude of
b. The rocket will eventually fall to the ground at some point after its engines fail. We solve for
, then add 3 seconds to this time:
So the rocket stays in the air for a total of .
c. After the engine failure, the rocket traveled for about 34.6 seconds, so we evalute for this time
: