Answer:
23.96 N
Explanation:
From the question given above, the following data were obtained:
Mass of Chihuahua (m) = 3.63 kg
Velocity (v) = 3.3m/s
Time (t) = 0.50 s
Force (F) =?
Next, we shall determine the acceleration of the Chihuahua. This can be obtained as follow:
Velocity (v) = 3.3m/s
Time (t) = 0.50 s
Acceleration (a) =?
a = v/t
a = 3.3/0.5
a = 6.6 m/s²
Thus, the acceleration of the Chihuahua is 6.6 m/s².
Finally, we shall determine the force need to stop the Chihuahua as shown below:
Mass of Chihuahua (m) = 3.63 kg
Acceleration (a) = 6.6 m/s².
Force (F) =?
F = ma
F = 3.63 × 6.6
F = 23.96 N
Therefore, a force of 23.96 N is needed to stop the Chihuahua.
215
I am assuming that those are the width and length. So to find area all you have to do is multiply the two because lw = a. 12 1/2*17 1/5 = 215
25/2*86/5 = 2150/10 = 215
Black-spotted skin coat as camouflage while stalking prey.
Survival = avoiding predators or capturing prey successfully
Answer:
pull over and bleed them to see if you need a new system then you should check you brake pads and see if their worn if all else fails pull over and kiss your bum goodbye
Explanation:
Answer:
m = 9795.9 kg
Explanation:
v = 35 m/s
KE = 6,000,000 J
Plug those values into the following equation:

6,000,000 J = (1/2)(35^2)m
---> m = 9795.9 kg