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fenix001 [56]
3 years ago
5

I need to know how to simplify questions like these.

Mathematics
1 answer:
exis [7]3 years ago
7 0

Answer:

<u>3x^7</u>

y^z

Step-by-step explanation:

Any <u>non-zero</u> expression raised to the <u>power</u> of 0 equals 1.

<u>3x^3y^-1z^-1</u>   -->  <u>3x^3y^-1z^-1</u>   -->  <u>3</u><u>x^7</u><u>y^-1z^-1</u>

x^-4×1z^0              x^-4×1×1                     1×1

Any expression multiplied by 1 remains the same.

<u>3x^7y^-1z^-1</u>

        1

Any expression multiplied by 1 remains the same.

3x^7y^-1z^-1

Any expression raised to the <u>power</u> of -1 equals its <u>reciprocal</u>

3x^7× 1/y × 1/z

Calculate the <u>product</u>

<u>3x^7</u>

y^z

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Im is the Imaginary Axis which is the imaginary number in the equation (37)

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Which equation has infinitely many solutions?
ipn [44]

Answer:

Equation C. 5.1 + 2y + 1.2 = -2 + 2y + 8.3

Step-by-step explanation:

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2 years ago
Lucy’s rectangular garden is 15ft long and 12 ft wide. She adds a right triangle to her garden plan, so that the triangle’s heig
KIM [24]
Okay, so lets break this down.

First of all, we have the rectangular garden with a length of 15ft and a width of 12feet.  We need to find the area of this which is pretty simple.  This would be 15ft times 12ft which is 180ft².

Okay, now time for the triangle.  The way that it words it may be confusing but I can draw you a picture of what it looks like (its a quick draw so it looks kinda bad).

But, for the triangle we are going to extend the 12ft line (shorter side; width) and create a line that is 7 feet long.  Then, we are going to find the midpoint of the 15ft side and connect that with the end point of the triangle.

Since its on the longer side and its the midpoint, the triangle is going to have a base of 7.5ft (half of 15).  Then, the height is 7ft as included in the question.

Now to solve the area of a right triangle, you can use 1/2(bh).  So 1/2 of the base times height.

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Now, all you gotta do is add the 26.25ft² and the 180ft² together and you get 206.25ft²

4 0
2 years ago
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