The initial momentum of the system can be expressed as,
The final momentum of the system can be given as,
According to conservation of momentum,
Plug in the known expressions,
Initially, the second mass move towards the first mass therefore the initial speed of second mass will be taken as negative and the recoil velocity of first mass is also taken as negative.
Plug in the known values,
Thus, the final velocity of second mass is 2.99 m/s.
You find net charge by subtracting the number of electrons from the number of protons (since protons are positive and electrons are negative). 9 - 10 = -1
The change in the Gibb's free energy per mole (G) is 1.96 J.
The given parameters:
- Density of the ice, ρ = 917 kg/m³
- Initial pressure, P₁ = 1.0 bar
- Final pressure, P₂ = 2.0 bar
- Temperature, T = - 10 C
- Mass of water = 18 g
The change in the Gibb's free energy per mole (G) is calculated as follows;
where;
V is the volume of the ice
Change in pressure;
The change in the Gibb's free energy per mole (G);
Thus, the change in the Gibb's free energy per mole (G) is 1.96 J.
Learn more about Gibb's free energy here: brainly.com/question/10012881
Answer:
4. both blocks will both have the same amount of kinetic energy.
Explanation:
When the blocks are released free from the compression force, the spring exerts equal and opposite force on each block but the block with heavier (double) mass will attain slower ( half ) speed as compared to the lighter block according to the law of inertia. This works in synchronization to energy conservation.
Spring force is given as:
where: length of compression in the spring
<u>We know kinetic energy is given by:</u>
Hence the kinetic energy of both the blocks is equal when they are released to move free.
Answer:
Angular acceleration = 5 rad /s ^2
Kinetic energy = 0.391 J
Work done = 0.391 J
P =6.25 W
Explanation:
The torque is given as moment of inertia × angular acceleration
angular acceleration = torque/ moment of inertia
= 10/2= 5 rad/ s^2
The kinetic energy is = 1/2 Iw^2
w = angular acceleration/time
=5/8= 0.625 rad /s
1/2 × 2× 0.625^2
=0.391 J
The work done is equal to the kinetic energy of the motor at this time
W= 0.391 J
The average power is = torque × angular speed
= 10× 0.625
P = 6.25 W