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4 years ago

Are enzyme-catalyzed reactions examples of homo- geneous or heterogeneous catalysis? Explain.

Chemistry

1 answer:

Tanzania [10]4 years ago

8 0

Answer:Yes,enzymes are catalyzed reactions

Explanation:Enzymes are protein that speeds up chemical reactions. Enzyme catalyzed reaction are divided into two:

Homogeneous reaction

Heterogeneous reaction.

Homogeneous catalysts occupy the same phase as the reaction mixture, while heterogeneous catalysts occupy a different phase.

Acid catalysis, organometallic catalysis, and enzymatic catalysis are examples of homogeneous catalysis.

Vanadium oxide (V2 O5) is a brown/yellow solid on which the oxygen and sulfur dioxide can adsorb in order to react with each other to form sulfuric acid.

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Fe2O3 + 2Al -> Al2O3 + 2Fe

pashok25 [27]

Fe2O3 + 2Al ---> Al2O3 + 2Fe
Mole ratio Fe2O3 : Al = 1:2
No. of moles of Fe2O3 = Mass/RMM = 250 / (55.8 * 2 + 16 * 3) = 1.56641604 moles
No. of moles of Al = 150/27 = 5.555555555 moles.
Mole ratio 1 : 2. 1.56641604 * 2 = 3.13283208 moles of Al, but you have 5.555555555 moles of Al. So Al is in excess. All of it won't react.

So take the Fe2O3 and Fe ratio to calculate the mass of iron metal that can be prepared.
RMM of Fe2O3 / Mass of Fe2O3 = RMM of 2Fe / Mass of Fe 159.6 / 250 = 111.6 / x x = 174.8 g of Fe

7 0

3 years ago

Read 2 more answers

Which of the following would form a heterogeneous mixture?

fiasKO [112]

The Answer:C. A mixture of an electrolyte and water.

8 0

3 years ago

Name the region of the atom where electrons are located.

Alchen [17]

Answer:

The electrons are found on the atomic nucleus.

Explanation:

5 0

3 years ago

Read 2 more answers

Calculate the specific heat capacity for a 22.7-g sample of lead that absorbs 237 J when its temperature increases from 29.8 °C

soldier1979 [14.2K]

Answer:

$\boxed {\boxed {\sf c\approx 0.159 \ J/ g \textdegree C}}$

Explanation:

We are asked to find the specific heat capacity of a sample of lead. The formula for calculating the specific heat capacity is:

$c= \frac{Q}{m \times \Delta T}$

The heat absorbed (Q) is 237 Joules. The mass of the lead sample (m) is 22.7 grams. The change in temperature (ΔT) is the difference between the final temperature and the initial temperature. The temperature increases from 29.8 °C to 95.6 °C.

ΔT = final temperature -inital temperature
ΔT= 95.6 °C - 29.8 °C = 65.8 °C

Now we know all three variables and can substitute them into the formula.

Q= 237 J
m= 22.7 g
ΔT = 65.8 °C

$c= \frac {237 \ J}{22.7 \ g \ \times \ 65.8 \textdegree C}$

Solve the denominator.

22.7 g * 65.8 °C = 1493.66 g °C

$c= \frac {237 \ J}{1493.66 \ g \textdegree C}$

Divide.

$c= 0.1586706479 J /g \textdegree C$

The original values of heat, temperature, and mass all have 3 significant figures, so our answer must have the same. For the number we found that is the thousandth place. The 6 in the ten-thousandth place tells us to round the 8 up to a 9.

$c \approx 0.159 \ J/g \textdegree C$

The specific heat capacity of lead is approximately 0.159 Joules per gram degree Celsius.

3 0

3 years ago

Can some type 1 paragraph about photosynthesis gas and become my friends and you might get brainlist

Dafna11 [192]

Answer:

Photosynthesis gas, is called carbon dioxide. Carbon Dioxide in this process is where the plants take in the dioxide and water, which is slowly reduced which gains electrons! :)

Explanation:

Hope this helps ! plz mark as brainliest!

7 0

3 years ago