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pogonyaev
3 years ago
11

To minimize animal stress, the use of should be minimized when handling cattle.

Chemistry
2 answers:
sp2606 [1]3 years ago
6 0

Answer:

Yes, that is true. Tame cattle do not mind being handled, touched, or have you near them. Those who are a bit wild, do not appreciate that.

Explanation:

(I have two cows who are both examples, one super tame, other very shy.)

klemol [59]3 years ago
3 0

The correct answer to this open question is the following.

To minimize animal stress, the use of sharp or solid objects, as well as prodding or kicking should be minimized when handling cattle.

It is also recommended to minimize the crossing of the herd through slippery surfaces to avoid the risk of falling. Remember that you have to take good care of your cattle. Have the proper and clean facilities, nourish the cattle well, and provide necessary food and medicine.

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Explanation:

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2 years ago
If you can smell your grandmother’s perfume from across the room, you are experiencing the result of which liquid property?
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2 years ago
If 200 ml of 0.15 M propionic acid (PA) is added to 300 ml of 0.02 M NaOH, what is the resulting pH of the solution? Round the a
vodomira [7]

Answer:

pH = 4.543

Explanation:

  • CH3CH2COOH  + H2O ↔ CH3CH2COO-  +  H3O+
  • pKa = - Log Ka

∴ Ka = [H3O+][CH3CH2COO-]/[CH3CH2COOH]

∴ pKa = 4.87

⇒ Ka = 1.349 E-5 = [H3O+][CH3CH2COO-]/[CH3CH2COOH]

added 300 mL 0f 0.02 M NaOH:

⇒ <em>C</em> CH3CH2COOH = ((0.200 L)(0.15 M)) - ((0.300 L)(0.02 M))/(0.3 + 0.2)

⇒ <em>C</em> CH3CH2COOH = 0.048 M

⇒ <em>C</em> NaOH = (0.300 L)(0.02 M) / (0.3 +0.2) = 0.012 M

mass balance:

⇒ 0.048 + 0.012 = 0.06 M = [CH3CH2COO-] + [CH3CH2COOH].......(1)

charge balance:

⇒ [H3O+] + [Na+] = [CH3CH2COO-]

∴ [Na+] = 0.02 M

⇒ [CH3CH2COO-] = [H3O+] + 0.02 M.............(2)

(2) in (1):

⇒ [CH3CH2COOH] = 0.06 M - 0.02 M - [H3O+] = 0.04 M - [H3O+]

replacing in Ka:

⇒ 1.349 E-5 = [H3O+][([H3O+] + 0.02) / (0.04 - [H3O+])

⇒ (1.349 E-5)(0.04 - [H3O+]) = [H3O+]² + 0.02[H3O+]

⇒ 5.396 E-7 - 1.349 E-5[H3O+] = [H3O+]² + 0.02[H3O+]

⇒ [H3O+]² + 0.02001[H3O+] - 5.396 E-7 = 0

⇒ [H3O+ ] = 2.867 E-5 M

∴ pH = - Log [H3O+]

⇒ pH = 4.543

3 0
3 years ago
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lord [1]

Answer:

well what I think is that C is the correct answer

4 0
2 years ago
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