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3 years ago

To minimize animal stress, the use of should be minimized when handling cattle.

Chemistry

2 answers:

sp2606 [1]3 years ago

6 0

Answer:

Yes, that is true. Tame cattle do not mind being handled, touched, or have you near them. Those who are a bit wild, do not appreciate that.

Explanation:

(I have two cows who are both examples, one super tame, other very shy.)

klemol [59]3 years ago

3 0

The correct answer to this open question is the following.

To minimize animal stress, the use of sharp or solid objects, as well as prodding or kicking should be minimized when handling cattle.

It is also recommended to minimize the crossing of the herd through slippery surfaces to avoid the risk of falling. Remember that you have to take good care of your cattle. Have the proper and clean facilities, nourish the cattle well, and provide necessary food and medicine.

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Determine the work done by an ideal gas while expanding by a volume of 0.25 L against an external pressure of 1.50 atm (assume a

Sliva [168]

Answer : The value of work done by an ideal gas is, 37.9 J

Explanation :

Formula used :

Expansion work = External pressure of gas × Volume of gas

Expansion work = 1.50 atm × 0.25 L

Expansion work = 0.375 L.atm

Conversion used : (1 L.atm = 101.3 J)

Expansion work = 0.375 × 101.3 = 37.9 J

Therefore, the value of work done by an ideal gas is, 37.9 J

6 0

3 years ago

how many moles of sodium are present in a sample of sodium having a mass of 137 g? (molar mass is 23.0g)

vivado [14]

Answer:

5.95 moles

Explanation:

No of moles = given mass / molar mass

No of moles = 137/23

= 5.95 moles

7 0

3 years ago

How does the energy of the activated complex compare with the energies of reactants and products? select one:

Free_Kalibri [48]

Answer:

Option d. it is higher than the energy of both reactants and products

Explanation:

Activated complex, also known as transition state, is the intermediate structure formed in the course of a chemical reaction.

The activated complex is very unstable and of short life: it is at the peak of the potential chemical diagram, and can transform either into the reactants (backward) or the products (forward).

The activation energy of the reaction is the energy needed to reach the activated complex, then both reactants and products are lower in potential chemical energy than the activated complex, which is what explains why the activated complex can transform into one or another, reactants or products.

5 0

3 years ago

The reaction between nitrogen dioxide and carbon monoxide is NO2(g)+CO(g)→NO(g)+CO2(g)NO2(g)+CO(g)→NO(g)+CO2(g) The rate constan

Alex17521 [72]

Answer : The rate constant at 525 K is, $0.0606M^{-1}s^{-1}$

Explanation :

According to the Arrhenius equation,

$K=A\times e^{\frac{-Ea}{RT}}$

or,

$\log (\frac{K_2}{K_1})=\frac{Ea}{2.303\times R}[\frac{1}{T_1}-\frac{1}{T_2}]$

where,

$K_1$ = rate constant at $701K$ = $2.57M^{-1}s^{-1}$

$K_2$ = rate constant at $525K$ = ?

$Ea$ = activation energy for the reaction = $1.5\times 10^2kJ/mol=1.5\times 10^5J/mol$

R = gas constant = 8.314 J/mole.K

$T_1$ = initial temperature = 701 K

$T_2$ = final temperature = 525 K

Now put all the given values in this formula, we get:

$\log (\frac{K_2}{2.57M^{-1}s^{-1}})=\frac{1.5\times 10^5J/mol}{2.303\times 8.314J/mole.K}[\frac{1}{701K}-\frac{1}{525K}]$

$K_2=0.0606M^{-1}s^{-1}$

Therefore, the rate constant at 525 K is, $0.0606M^{-1}s^{-1}$

8 0

3 years ago

Which species should have the shortest bond length?

aev [14]

Answer:

The correct option is: A) N₂

Explanation:

The Bond length of a chemical bond is the length of a chemical bond formed between two given atoms.

Bond length is inversely proportional to the bond order of the chemical bond, which is the total number of bonds between two atoms. Thus as the bond order increases, the bond length decreases.

A) N₂: The nitrogen-nitrogen bond in dinitrogen is a triple bond (N≡N).

Thus the bond order = 3.

B) O₂: The oxygen-oxygen bond in dioxygen is a triple bond (O=O).

Thus the bond order = 2.

C) SO₂: Sulfur dioxide is a resonance stabilized molecule and its resonance hybrid shows that the sulfur-oxygen bond in sulfur dioxide is a partial double bond.

Thus the bond order = 1.5

D) SO₃: Sulfur trioxide is a resonance stabilized molecule and its resonance hybrid shows that the sulfur-oxygen bond in sulfur trioxide is a partial double bond.

Thus the bond order = 1.33

Since the bond order of N₂ is the largest, therefore, the N-N bond length is the shortest.

3 0

3 years ago